A ball of mass 179 g is thrown with an initial velocity of 25 m/s at an angle of 30° with the horizontal direction. Ignore air resistance. What is the momentum of the ball after 0.8 s? (Do this problem by finding the components of the momentum first and then constructing the magnitude and direction of the momentum vector from the components. Find the magnitude in kg - m/s and the direction in degrees counterclockwise from the +x-axis. Assume the +x-axis points horizontally to the right.) v = (25 m/s)v 30° magnitude kg · m/s direction ° counterclockwise from the +x-axis

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A ball of mass 179 g is thrown with an initial velocity of 25 m/s at an angle of 30° with the horizontal direction. Ignore air resistance. What is the momentum of the ball after 0.8 s? (Do this problem by finding the components of the momentum first and then constructing the magnitude and direction of the momentum vector from the components. Find the magnitude in kg · m/s and the direction in degrees counterclockwise from the +x-axis. Assume the +x-axis points horizontally to the right.)

magnitude _____ kg · m/s

direction ______ ° counterclockwise from the +x-axis

v = (25 m/s)û
%3D
30°
magnitude
kg · m/s
direction
counterclockwise from the +x-axis
Transcribed Image Text:v = (25 m/s)û %3D 30° magnitude kg · m/s direction counterclockwise from the +x-axis
A ball of mass 179 g is thrown with an initial velocity of 25 m/s at an angle of 30° with the horizontal direction. Ignore air resistance. What is the momentum of the ball after 0.8 s?
(Do this problem by finding the components of the momentum first and then constructing the magnitude and direction of the momentum vector from the components. Find the
magnitude in kg · m/s and the direction in degrees counterclockwise from the +x-axis. Assume the +x-axis points horizontally to the right.)
v = (25 m/s)v
30°
| kg · m/s
° counterclockwise from the +x-axis
magnitude
direction
Transcribed Image Text:A ball of mass 179 g is thrown with an initial velocity of 25 m/s at an angle of 30° with the horizontal direction. Ignore air resistance. What is the momentum of the ball after 0.8 s? (Do this problem by finding the components of the momentum first and then constructing the magnitude and direction of the momentum vector from the components. Find the magnitude in kg · m/s and the direction in degrees counterclockwise from the +x-axis. Assume the +x-axis points horizontally to the right.) v = (25 m/s)v 30° | kg · m/s ° counterclockwise from the +x-axis magnitude direction
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