A ball is thrown with an initial velocity of (30 m/s) at an angle of (60°) above the horizontal, as shown in figure below. Find : (a) The maximum height of the ball? Answer : ( Ymax = 34.5m) (b) The time to rise to the top of the trajectory? Answer:(t,=2.65s) (@) The total time the ball is in the air? Answer: (t:=5.305)
A ball is thrown with an initial velocity of (30 m/s) at an angle of (60°) above the horizontal, as shown in figure below. Find : (a) The maximum height of the ball? Answer : ( Ymax = 34.5m) (b) The time to rise to the top of the trajectory? Answer:(t,=2.65s) (@) The total time the ball is in the air? Answer: (t:=5.305)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A ball is thrown with an initial velocity of (30 m/s) at an angle of (60°) above the horizontal, as shown in figure below. Find : (a) The maximum height of the ball? Answer : ( Ymax = 34.5m) (b) The time to rise to the top of the trajectory? Answer:(t,=2.65s) (@) The total time the ball is in the air? Answer: (t:=5.305)
![Problem 1.6a
Projectile motion in two dimensions
A ball is thrown with an initial velocity of (30 m/s) at an angle
of (60°) above the horizontal, as shown in figure below. Find :
(a) The maximum height of the ball?
Answer : ( ymax = 34.5 m )
(b) The time to rise to the top of the trajectory?
Answer : ( t = 2.65 s )
(e) The total time the ball is in the air?
Answer : (t = 5.30 s)
Ymas
-Range](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffab565f0-8090-45e7-9dfb-e06824758d8c%2F9ef9d528-af2c-4ea8-9139-2828d69bf2d3%2Fz5y03w_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 1.6a
Projectile motion in two dimensions
A ball is thrown with an initial velocity of (30 m/s) at an angle
of (60°) above the horizontal, as shown in figure below. Find :
(a) The maximum height of the ball?
Answer : ( ymax = 34.5 m )
(b) The time to rise to the top of the trajectory?
Answer : ( t = 2.65 s )
(e) The total time the ball is in the air?
Answer : (t = 5.30 s)
Ymas
-Range
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