A ball is thrown with an initial velocity of (30 m/s) at an angle of (60°) above the horizontal, as shown in figure below. Find : (a) The maximum height of the ball? Answer : ( Ymax = 34.5m) (b) The time to rise to the top of the trajectory? Answer:(t,=2.65s) (@) The total time the ball is in the air? Answer: (t:=5.305)

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Chapter1: Units, Trigonometry. And Vectors
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A ball is thrown with an initial velocity of (30 m/s) at an angle of (60°) above the horizontal, as shown in figure below. Find : (a) The maximum height of the ball? Answer : ( Ymax = 34.5m) (b) The time to rise to the top of the trajectory? Answer:(t,=2.65s) (@) The total time the ball is in the air? Answer: (t:=5.305)
Problem 1.6a
Projectile motion in two dimensions
A ball is thrown with an initial velocity of (30 m/s) at an angle
of (60°) above the horizontal, as shown in figure below. Find :
(a) The maximum height of the ball?
Answer : ( ymax = 34.5 m )
(b) The time to rise to the top of the trajectory?
Answer : ( t = 2.65 s )
(e) The total time the ball is in the air?
Answer : (t = 5.30 s)
Ymas
-Range
Transcribed Image Text:Problem 1.6a Projectile motion in two dimensions A ball is thrown with an initial velocity of (30 m/s) at an angle of (60°) above the horizontal, as shown in figure below. Find : (a) The maximum height of the ball? Answer : ( ymax = 34.5 m ) (b) The time to rise to the top of the trajectory? Answer : ( t = 2.65 s ) (e) The total time the ball is in the air? Answer : (t = 5.30 s) Ymas -Range
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