A ball is thrown straight upwards with an initial velocity of vo = 40 m/s from a height of 1 meter above the ground. The height of the ball as a function of time measured in seconds after it is thrown is given (roughly) by h(t) = 1 + 40t - 4.9t2. (c) What is the instantaneous accelerations after 4s?

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A ball is thrown straight upwards with an initial velocity of vo = 40 m/s from a height of 1 meter above the ground. The height of the ball as a function of time measured in seconds after it is thrown is given (roughly) by h(t) = 1 + 40t - 4.9t2.
(c) What is the instantaneous accelerations after 4s?

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