A ball is thrown straight up with an initial velocity of 224 ft/sec, so its height (in feet) is given by h(t)=224t-16t². b. Find the average velocity of the ball over the interval [4,4.1] c. When will the ball hit the ground? d. Find the inverse function that gives the time t at which the ball is at height h as the ball travels downward.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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The problem involves the motion of a ball thrown straight upward with an initial velocity of 224 ft/sec. The height of the ball at time \( t \) is given by the function:

\[ h(t) = 224t - 16t^2 \]

**Questions:**

a. (Not specified.)

b. Find the average velocity of the ball over the interval \([4, 4.1]\).

c. Determine when the ball will hit the ground.

d. Find the inverse function that provides the time \( t \) at which the ball is at a height \( h \) while traveling downward.

e. Find the time at which the ball will be descending and at a height of 720 feet above the ground.

f. Create a table of values and record the average velocity in the intervals shortly before the ball hits the ground. Assume the answer to when it hits the ground is \( b \).

**Table:**

| Time Frame                             | Time Interval     | Average Velocity |
|----------------------------------------|-------------------|------------------|
| 1 second before hitting ground         |                   |                  |
| ½ second before hitting ground         |                   |                  |
| 0.1 second before hitting ground       |                   |                  |
| 0.01 seconds before hitting ground     |                   |                  |
| 0.001 seconds before hitting ground    |                   |                  |

g. Estimate the speed of the ball immediately before it hits the ground.

**Explanation:**

- The function \( h(t) = 224t - 16t^2 \) represents the height in feet of the ball at any time \( t \).
- The average velocity over an interval can be calculated using the change in height divided by the change in time.
- When the ball hits the ground, \( h(t) = 0 \).
- The inverse function would allow calculation of \( t \) given \( h \) for the downward path.
- Understanding these concepts is critical in analyzing the motion of objects in physics, specifically under the influence of gravity.
Transcribed Image Text:The problem involves the motion of a ball thrown straight upward with an initial velocity of 224 ft/sec. The height of the ball at time \( t \) is given by the function: \[ h(t) = 224t - 16t^2 \] **Questions:** a. (Not specified.) b. Find the average velocity of the ball over the interval \([4, 4.1]\). c. Determine when the ball will hit the ground. d. Find the inverse function that provides the time \( t \) at which the ball is at a height \( h \) while traveling downward. e. Find the time at which the ball will be descending and at a height of 720 feet above the ground. f. Create a table of values and record the average velocity in the intervals shortly before the ball hits the ground. Assume the answer to when it hits the ground is \( b \). **Table:** | Time Frame | Time Interval | Average Velocity | |----------------------------------------|-------------------|------------------| | 1 second before hitting ground | | | | ½ second before hitting ground | | | | 0.1 second before hitting ground | | | | 0.01 seconds before hitting ground | | | | 0.001 seconds before hitting ground | | | g. Estimate the speed of the ball immediately before it hits the ground. **Explanation:** - The function \( h(t) = 224t - 16t^2 \) represents the height in feet of the ball at any time \( t \). - The average velocity over an interval can be calculated using the change in height divided by the change in time. - When the ball hits the ground, \( h(t) = 0 \). - The inverse function would allow calculation of \( t \) given \( h \) for the downward path. - Understanding these concepts is critical in analyzing the motion of objects in physics, specifically under the influence of gravity.
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