A ball is thrown straight up with an initial speed of 12 m/s. What are the velocity and acceleration when it is at the top of its trajectory? Select all apply. v = 12 m/s a = 0 O v = 0 v = -12 m/s a = 9.8 m/s2 a = -9.8 m/s2

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A ball is thrown straight up with an initial speed of 12 m/s. What are the velocity and acceleration when it is at the top of its trajectory? Select all apply.
v = 12 m/s
a = 0
O v = 0
v = -12 m/s
9.8 m/s2
a =
a =
-9.8 m/s2
Transcribed Image Text:A ball is thrown straight up with an initial speed of 12 m/s. What are the velocity and acceleration when it is at the top of its trajectory? Select all apply. v = 12 m/s a = 0 O v = 0 v = -12 m/s 9.8 m/s2 a = a = -9.8 m/s2
Expert Solution
Step 1

In a projectile motion:

The object starts from zero and reaches the highest point of the trajectory.

After reaching the highest point, it starts coming towards the ground.

Formula used:

a = dvdt

here, a is the acceleration, v is the velocity and dvdt is the change in the velocity.

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