A ball is thrown at an angle of 30° from the top of a building 0.10 km high. The ball strikes the ground at a point 125 m horizontally away from and below the point of release. (a)What is the initial speed of the ball? (b) What is the speed of the ball just before it strikes the ground?
A ball is thrown at an angle of 30° from the top of a building 0.10 km high. The ball strikes the ground at a point 125 m horizontally away from and below the point of release. (a)What is the initial speed of the ball? (b) What is the speed of the ball just before it strikes the ground?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Projectile Motion Problem**
**Problem Statement:**
A ball is thrown at an angle of 30° from the top of a building 0.10 km high. The ball strikes the ground at a point 125 m horizontally away from and below the point of release.
**Questions:**
(a) What is the initial speed of the ball?
(b) What is the speed of the ball just before it strikes the ground?
**Instructions for Solving:**
1. **Understand the given information:**
- Angle of projection, \( \theta = 30^{\circ} \)
- Height of the building, \( h = 0.10 \, \text{km} = 100 \, \text{m} \)
- Horizontal distance from the point of release to the point where the ball hits the ground, \( R = 125 \, \text{m} \)
2. **Break down the components of the projectile motion:**
- Decompose the initial velocity \( v_0 \) into horizontal (\( v_{0x} \)) and vertical (\( v_{0y} \)) components:
- \( v_{0x} = v_0 \cos 30^{\circ} \)
- \( v_{0y} = v_0 \sin 30^{\circ} \)
3. **Use the kinematic equations to solve for the initial speed \( v_0 \):**
- Horizontal motion:
\[ R = v_{0x} t \]
\[ 125 = v_0 \cos 30^{\circ} \times t \]
- Vertical motion:
- Use the equation for displacement:
\[ y = v_{0y} t - \frac{1}{2} g t^2 \]
\[ -100 = (v_0 \sin 30^{\circ})t - \frac{1}{2} g t^2 \]
4. **Solve the system of equations to find \( t \) (time of flight) and \( v_0 \):**
5. **Calculate the final speed of the ball just before it strikes the ground:**
- Use the equations for horizontal and vertical components of velocity just before impact:
- \( v_{x} = v_{0x} \)
- \( v_{y} = v](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7a908816-dcaf-4aa4-8dd6-7dd2f0aea84f%2F8f8167a8-a1b6-4b5d-8195-864cb5616bc2%2Fyeq63w.png&w=3840&q=75)
Transcribed Image Text:**Projectile Motion Problem**
**Problem Statement:**
A ball is thrown at an angle of 30° from the top of a building 0.10 km high. The ball strikes the ground at a point 125 m horizontally away from and below the point of release.
**Questions:**
(a) What is the initial speed of the ball?
(b) What is the speed of the ball just before it strikes the ground?
**Instructions for Solving:**
1. **Understand the given information:**
- Angle of projection, \( \theta = 30^{\circ} \)
- Height of the building, \( h = 0.10 \, \text{km} = 100 \, \text{m} \)
- Horizontal distance from the point of release to the point where the ball hits the ground, \( R = 125 \, \text{m} \)
2. **Break down the components of the projectile motion:**
- Decompose the initial velocity \( v_0 \) into horizontal (\( v_{0x} \)) and vertical (\( v_{0y} \)) components:
- \( v_{0x} = v_0 \cos 30^{\circ} \)
- \( v_{0y} = v_0 \sin 30^{\circ} \)
3. **Use the kinematic equations to solve for the initial speed \( v_0 \):**
- Horizontal motion:
\[ R = v_{0x} t \]
\[ 125 = v_0 \cos 30^{\circ} \times t \]
- Vertical motion:
- Use the equation for displacement:
\[ y = v_{0y} t - \frac{1}{2} g t^2 \]
\[ -100 = (v_0 \sin 30^{\circ})t - \frac{1}{2} g t^2 \]
4. **Solve the system of equations to find \( t \) (time of flight) and \( v_0 \):**
5. **Calculate the final speed of the ball just before it strikes the ground:**
- Use the equations for horizontal and vertical components of velocity just before impact:
- \( v_{x} = v_{0x} \)
- \( v_{y} = v
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