A ball is launched vertically upward with a velocity of 192 ft/s, so its position function can be modeled as s(t)=−16t^2+192t. What is the velocity of the ball when it first reaches a vertical height of 560 ft?
A ball is launched vertically upward with a velocity of 192 ft/s, so its position function can be modeled as s(t)=−16t^2+192t. What is the velocity of the ball when it first reaches a vertical height of 560 ft?
Related questions
Question
8.
A ball is launched vertically upward with a velocity of 192 ft/s, so its position function can be modeled as s(t)=−16t^2+192t. What is the velocity of the ball when it first reaches a vertical height of 560 ft?
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps
