A ball is launched straight up in the air from a height of 5 feet. Its velocity (feet/second) t seconds after launch is given by f(t) = -32t+284. Between 1 seconds and 5 seconds the ball's height changed by feet. (Round answer to nearest tenth.)
A ball is launched straight up in the air from a height of 5 feet. Its velocity (feet/second) t seconds after launch is given by f(t) = -32t+284. Between 1 seconds and 5 seconds the ball's height changed by feet. (Round answer to nearest tenth.)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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![A ball is launched straight up in the air from a height of 5 feet. Its velocity (feet/second) t seconds after launch is given by f(t)= -32t + 284.
feet.
Between 1 seconds and 5 seconds the ball's height changed by
(Round answer to nearest tenth.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7ed63b8c-5f2a-459c-b7ed-e6789166686d%2F246b6bb4-893a-4378-a718-30061c8aa98f%2Fur7k42_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A ball is launched straight up in the air from a height of 5 feet. Its velocity (feet/second) t seconds after launch is given by f(t)= -32t + 284.
feet.
Between 1 seconds and 5 seconds the ball's height changed by
(Round answer to nearest tenth.)
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