A ball has a diameter of 46 mm and falls in honey with a terminal velocity of0.3 m/s. For honey, take ph = 1360 kg/m³ and h = 0.04 m²/s. Note: Thevolume of a sphere is V=³. (Figure 1)Figure1 of 1Part ADetermine the mass of the ball.Express your answer to three significant figures and include the appropriate units.Mim= 6.32μАkgSubmit Previous Answers Request AnswerProvide Feedback?X Incorrect; Try Again; 2 attempts remaining

Name: A ball has a diameter of 46 mm and falls in honey with a terminal vel
Uploaded: 2024-03-20T06:56:55.000Z
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Description: A ball has a diameter of 46 mm and falls in honey with a terminal velocity of0.3 m/s. For honey, take ph = 1360 kg/m³ and h = 0.04 m²/s. Note: Thevolume of a sphere is V=³. (Figure 1)Figure1 of 1Part ADetermine the mass of the ball.Express your answ

given: d = 46 mm = 0.046m V = 0.3 m/s ρₕ = 1360 kg/m³ υₕ = 0.04 m²/s Volume of ball = 4/3πr³ ⇒Vₛ = 43×π×(0.0462)³ ⇒Vₛ = 5.0965 x 10-5 m³The terminal velocity of ball having density ρₛ falling inside the fluid honey having density ρₕ and kinematic viscosity υₕ is expressed as V = (ρₛ-ρₕ)gd²18υₕ ⇒0.3 = (ρₛ-1360)×9.81×0.046²18×0.04 ⇒10.4056 = ρₛ - 1360 ⇒∴ ρₛ = 1370.4056 kg/m³since density of sphere ( ball) is ρₛ = mass/ volume = mₛ/Vₛ ⇒1370.4056 = mₛ5.0965×10-5 ⇒mₛ = (1370.4056)*(5.0965x10-5) ⇒mₛ = 0.0698 kg Hence mass of ball(sphere) is 0.0698 kg