A ball experiences an acceleration of 0.25 m/s2 in the +x-direction while moving at 3.4m/s along the +y-direction. What are the (a)velocity (b)position of the ball after 4.0 s?
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A ball experiences an acceleration of 0.25 m/s2 in the +x-direction while moving at 3.4m/s along the +y-direction. What are the (a)velocity (b)position of the ball after 4.0 s?
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- A puck is moving on an air hockey table. Relative to an x, y coordinate system at time t = 0s, the x components of the puck's initial velocity and acceleration are vox = +7.2 m/s and ax = +1.1 m/s². They components of the puck's initial velocity and acceleration are Voy=+3.6 m/s and ay = -1.5 m/s². Find (a) the magnitude v and (b) the direction of the puck's velocity at a time of t = 0.50 s. Specify the direction relative to the +x axis. (a) v = i (b) 0= degrees the +x axisCar A is traveling on a highway at a constant speed. Initial velocity A = 80 mi/h and is 380 ft from the entrance of an on-ramp when car B enters the acceleration lane at that point at a speedInitial speed B = 20.0 mi/h. Car B accelerates uniformly and enters the main traffic lane after traveling 290 ft in 3.3 s. It then continues to accelerate at the same rate until it reaches a speed of 80 mi/h, which it maintains. Determine the final distance between the two cars (in ft).Physics A miniature quadcopter is located at x, = 2.25 m and y, =-2.70 m at t = 0 and moves with an average velocity having components Yav, x = 1.70 m/s and Yav, y =-2.50 m/s. What are the x- coordinate and y-coordinate (in m) of the quadcopter's position at t = 1.60 s? x-coordinate = y-coordinate = Please help! Thank you in advance!
- A particle moves along the x axis. It is initially at the position 0.240 m, moving with velocity 0.150 m/s and acceleration -0.240 m/s?. Suppose it moves with constant acceleration for 4.80 s. (a) Find the position of the particle after this time. (b) Find its velocity at the end of this time interval. m/s We take the same particle and give it the same initial conditions as before. Instead of having a constant acceleration, it oscillates in simple harmonic motion for 4.80 s around the equilibrium position x = 0. Hint: the following problems are very sensitive to rounding, and you should keep all digits in your calculator. (c) Find the angular frequency of the oscillation. Hint: in SHM, a is proportional to x. /s (d) Find the amplitude of the oscillation. Hint: use conservation of energy. m (e) Find its phase constant e, if cosine is used for the equation of motion. Hint: when taking the inverse of a trig function, there are always two angles but your calculator will tell you only one…A ball is projected upward at time t = 0.0 s, from a point on a roof 10 m above the ground. The ball rises, then falls and strikes the ground. The initial velocity of the ball is 58.5 m/s. Consider all quantities as positive in the upward direction. At time 1-5.97 s, the velocity of the ball is closest to: 12 m/s Ozero O-175 m/s O +12 m/s O +175 m/sTaking north to be the positive y direction and east to be the positive x direction, particle’s position is given by r(t) = [(45.1 m/s)t]i + [(7.37 m)t2]j. At what time, in seconds, is the particle traveling directly northeast?