A ball at 1200K is allowed to cool down in air at an ambient temperature of 300K. Assuming heat is lost only due to radiation, the differential equation for the temperature of the ball is given by = -2.2067x1012(04 -81x10,0(0)=1200K do dt A- Find the temperature at = 300 seconds using Runge-Kutta 4th order method, Assume step size of h = 300 seconds.

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A ball at 1200K is allowed to cool down in air at an ambient temperature of 300K.
Assuming heat is lost only due to radiation, the differential equation for the temperature of
the ball is given by
= -2.2067x1012(04 -81x10,0(0)=1200K
do
dt
A- Find the temperature at = 300 seconds using Runge-Kutta 4th order
method, Assume step size of h = 300 seconds.
Transcribed Image Text:A ball at 1200K is allowed to cool down in air at an ambient temperature of 300K. Assuming heat is lost only due to radiation, the differential equation for the temperature of the ball is given by = -2.2067x1012(04 -81x10,0(0)=1200K do dt A- Find the temperature at = 300 seconds using Runge-Kutta 4th order method, Assume step size of h = 300 seconds.
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