Please solve the problem A balanced three-phase Y-connected generator with positive sequence has an impedance of 0.2 +j0.5 6 andan internal voltage of 140 V/o. The generator feeds a balanced three-phase Y-connected load having animpedance of 39 + j28 6. The impedance of the line connecting the generator to the load is 0.8 + jl.5 /o.The a-phase internal voltage of the generator is specified as the reference phasor.a) Calculate line voltages at the terminals of the generator.

Answered: Image /qna-images/answer/e0c209d4-2cfa-424f-9427-da46782660c3.jpg

A balanced three-phase Y-connected generator with positive sequence has an impedance of 0.2 + j0.5 6 and an internal voltage of 140 V/o. The generator feeds a balanced three-phase Y-connected load having an impedance of 39 + j28 V6. The impedance of the line connecting the generator to the load is 0.8 + jl.5 2/6. The a-phase internal voltage of the generator is specified as the reference phasor. a) Calculate line voltages at the terminals of the generator.

A balanced three-phase Y-connected generator with positive sequence has an impedance of 0.2 + j0.5 6 and an internal voltage of 140 V/o. The generator feeds a balanced three-phase Y-connected load having an impedance of 39 + j28 V6. The impedance of the line connecting the generator to the load is 0.8 + jl.5 2/6. The a-phase internal voltage of the generator is specified as the reference phasor. a) Calculate line voltages at the terminals of the generator.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.43P: Three single-phase transformers, each rated 10MVA,66.4/12.5kV,60Hz, with an equivalent series...

See similar textbooks

Similar questions

The total instantaneous power absorbed by a three-phase motor (under balanced steady-state conditions) as well as a balanced three-phase impedance load is (a) A constant (b) A function of time
If the load is connected to the generator thgrough an inductive line and the voltage at the load side is the same as the voltage at the terminals of the generator, which of the following must be true? O A. The reactive power is flowing from the generator to the load and from load to the generator at the same time. O B. The load is disconnected, and no power is delivered to the load. O C. The load has a poor power factor and it's absorbing too much reactive power. O D. None of the other choices are correct O E. The generator is unable to produce reactive power; therefore, the reactive power is flowing from the load to the generator.
The reactance of a generator is given as 0.1 pu based on the generator of 17 KV, 300 MVA. Determine the pu reactance on a base of 17 KV, 250 MVA. New pu reactance is.......
conductor radius is 0.75cm
X₂=0.1 1 XL +03 Soto X₁ = 0.2 X = 0.1 X = 0.1 Above is the one-line diagram of a simple power system. Each generator is represented by an emf behind the subtransient reactance. All impedances are expressed in per unit on a common base. All resistances and shunt capacitance are neglected. The generators are operating on no load at their rated voltage with their emfs in phase. A symmetrical fault occurs at bus 1 through a fault impedance Z, =j0.08 per unit. a) Using Thevenin's Theorem, determine the impedance to the point of fault and the fault current in per unit. b) Find the bus voltages and line currents during the fault. 2 O oto
A three-phase star-connected alternator delivers at rated load a current I = 200 A under a voltage of 5 kV-50 Hz (between phases). The load is inductive of power factor equal to 0.87, the resistance of each stator winding is 0.292 and the speed of the rotor is n = 750 r.p.m. The sum of the constants losses and the stator Joule's losses and the rotor Joule's losses is 55 kW. The no load test, at rated frequency, gave: E-4200 V (between phases) for an excitation current lexc = 40 A. The short-circuit test, for an excitation current lexc = 40 A, gave a short-circuit current in the stator windings Ise =2.5 kA. 1- Calculate the numbers of poles of the alternator. 2- Calculate the synchronous reactance (X). 3- Calculate the electromotive force of the alternator (E) between phases for the same excitation current. 4- Calculate the power absorbed by the alternator (Pa).
An 11 KV generating station has four identical 3-phase alternators A,B,C and D and each of 10 MVA and 12% reactance. There are two sections of bus-bar, P and O linked by a reactor rated at connected to bus-bar section MVA with 24% reactance. Alternators A and B are and alternators C and D to bus-bar section Q. From each section, load is taken through a number of 6 MVA, 11/66KV step-up transformers, each having a reactance of 3%. Calculate the current fed into a fault if a short-circuit occurs on all phases near the high-voltage terminals of one of the transformers at the bus-bar section Q. 10 MVA 10 MVA 12% 11 11 KV 10 MVA 24% -000000 10 MVA 12% o Q 10 MVA 12% 0 11 KV 6 MVA WWW 3% /www
Please answer atleast four subparts
A generating station has the following daily load cycle: [10] Time 0-6 6-10 10-12 12-16 16-20 20-24 (Hours) Load 40 50 60 50 70 40 (MW) Draw the load curve and find (i) maximum demand (ii) units generated per day (iii) average load and (iv) load factor.
The shaft of a three-phase synchronous generator is rotating at 1800 RPM synchronous speed. This generator is supplying a load of 16.5 KW, 0.8 PF lagging, with an efficiency of 85 %. The copper losses are neglected. Calculate the sum Pf&w + Pcore + Pstray , and the induced torque by this generator. Select one: O a. None O b. PF&w + Pcore + Pstray = 2475 W, and tind = 87.5 N.m. c. PE&w + Pcore + Pstray = 2911.7 W, and tind = 87.5 N.m. O d. Pf&w + Pcore + Pstray = 2475 W, and tind = 102.9 N.m. O e. Pfgw + Pcore + Pstray = 3425.5 W, and tind = 102.9 N.m. Clear my choice
Khalid Abdulrahman Abdullah Alqasmi KA 05 Symm... 9 Search 8 Share O Comments Transitions Animations Slide Show Review View Help 1. A 3- phase, 30 MVA, 33 KV alternator has internal reactance of 4% and negligible resistance. Find the external reactance per phase to be connected in series with the alternator so that steady current on short circuit does not exceed 10 times the full load. Also find Find the full load current. d notes
A three phase star connected alternator has a resistance of 0.5 ohms per phase and a synchronous reactance of 5 ohms per phase. It is exited to give 6600 V (line) on open circuit. Determine the terminal voltage and voltage regulation on full load current of 130 A when the load pf is (i) 0.8 lagging (ii) 0.6 leading pf