A bag of M&M's has 8 red, 7 green, 3 blue, and 4 yellow M&M's. What is the probability of randomly picking: (Round to 4 decimal places) a) a yellow? b) a blue or green? c) an orange?
A bag of M&M's has 8 red, 7 green, 3 blue, and 4 yellow M&M's. What is the probability of randomly picking: (Round to 4 decimal places) a) a yellow? b) a blue or green? c) an orange?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![### Question 3
**Problem Statement:**
A bag of M&M's has:
- 8 red
- 7 green
- 3 blue
- 4 yellow
**Question:**
What is the probability of randomly picking (Round to 4 decimal places):
a) a yellow M&M?
b) a blue or green M&M?
c) an orange M&M?
**Answer Fields:**
a) a yellow? ________
b) a blue or green? ________
c) an orange? ________
**Explanation:**
To solve each sub-question, you need to know the total number of M&M's and apply the basic probability formula:
\[ \text{Probability} = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Possible Outcomes}} \]
1. Calculate the total number of M&M's:
\[ 8 \text{ (red)} + 7 \text{ (green)} + 3 \text{ (blue)} + 4 \text{ (yellow)} = 22 \text{ M&Ms} \]
2. Apply the probability formula for each question:
**a)** Probability of picking a yellow M&M:
\[ \frac{4 \text{ (yellow M&Ms)}}{22 \text{ (total M&Ms)}} \]
**b)** Probability of picking a blue or green M&M:
\[ \frac{3 \text{ (blue M&Ms)} + 7 \text{ (green M&Ms)}}{22 \text{ (total M&Ms)}} \]
**c)** Probability of picking an orange M&M (assuming orange M&Ms are not present):
\[ \frac{0 \text{ (orange M&Ms)}}{22 \text{ (total M&Ms)}} \]
Fill in the appropriate values in the provided answer fields using the probability formulas above.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbed7ab37-3726-4b83-a741-6ed60a3ee8a9%2Fbb10bb84-6e05-4d10-80ce-4704aa0a2f59%2Fai534a_processed.png&w=3840&q=75)
Transcribed Image Text:### Question 3
**Problem Statement:**
A bag of M&M's has:
- 8 red
- 7 green
- 3 blue
- 4 yellow
**Question:**
What is the probability of randomly picking (Round to 4 decimal places):
a) a yellow M&M?
b) a blue or green M&M?
c) an orange M&M?
**Answer Fields:**
a) a yellow? ________
b) a blue or green? ________
c) an orange? ________
**Explanation:**
To solve each sub-question, you need to know the total number of M&M's and apply the basic probability formula:
\[ \text{Probability} = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Possible Outcomes}} \]
1. Calculate the total number of M&M's:
\[ 8 \text{ (red)} + 7 \text{ (green)} + 3 \text{ (blue)} + 4 \text{ (yellow)} = 22 \text{ M&Ms} \]
2. Apply the probability formula for each question:
**a)** Probability of picking a yellow M&M:
\[ \frac{4 \text{ (yellow M&Ms)}}{22 \text{ (total M&Ms)}} \]
**b)** Probability of picking a blue or green M&M:
\[ \frac{3 \text{ (blue M&Ms)} + 7 \text{ (green M&Ms)}}{22 \text{ (total M&Ms)}} \]
**c)** Probability of picking an orange M&M (assuming orange M&Ms are not present):
\[ \frac{0 \text{ (orange M&Ms)}}{22 \text{ (total M&Ms)}} \]
Fill in the appropriate values in the provided answer fields using the probability formulas above.
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