A bag of coins contains nine pennies, six nickels, four dimes, and three quarters. Assuming that the coins of any one denomination are identical, in how many ways can 10 coins be selected?   The answer is C(13,3) - C(3,3) - C(6,3) - C(8,3) - C(9,3) + C(4,3) I just have no idea where to start. Thanks!

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