A bag contains 8 yellow marbles, 7 white marbles, 6 green marbles. If one marble is drawn from the bag then replaced, what is the probability of drawing a yellow marble then a green marble? In a number guessing game. You ask a person to guess a number from one 1 to 10. If the person makes a random guess, what is the probability their guess will be less than 9? A bag contains 7 red marbles, 6 green marbles, 8 white marbles. If one marble is drawn from the bag but not replaced, what is the probability of drawing a red marble then a white marble?

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
icon
Related questions
Question
**Marble Probabilities and Number Guessing Game: Understanding Probability**

1. **Marble Probability Question 1: Replacement Scenario**

   A bag contains 8 *yellow* marbles, 7 *white* marbles, and 6 *green* marbles. 
   
   - **Question:** If one marble is drawn from the bag and then replaced, what is the probability of drawing a *yellow* marble and then a *green* marble?
   
   - **Explanation:** For this scenario, calculate the probability of two independent events: drawing a yellow marble and then a green marble. Since the marble is replaced between draws, each draw is independent.

   \[ P(yellow) = \frac{8}{21} \]
   
   \[ P(green) = \frac{6}{21} \]
   
   \[ P(yellow \text{ then } green) = P(yellow) \times P(green) = \frac{8}{21} \times \frac{6}{21} \]

2. **Number Guessing Game: Range Probability**

   - **Scenario:** In a number guessing game, a person guesses a number from 1 to 10.

   - **Question:** What is the probability their guess will be less than 9?

   - **Explanation:** Calculate the probability of guessing numbers 1 through 8. 

   \[ P(<9) = \frac{8}{10} = \frac{4}{5} \]

3. **Marble Probability Question 2: Without Replacement Scenario**

   A bag contains 7 *red* marbles, 6 *green* marbles, and 8 *white* marbles.
   
   - **Question:** If one marble is drawn from the bag but not replaced, what is the probability of drawing a *red* marble and then a *white* marble?
   
   - **Explanation:** For this scenario, calculate the probability of two dependent events: drawing a red marble and then a white marble, with no replacement in between.

   \[ P(red) = \frac{7}{21} \]
   
   After one red marble is drawn, the total number of marbles is 20.

   \[ P(white | red) = \frac{8}{20} \]

   \[ P(red \text{ then } white) = P(red) \times P(white | red
Transcribed Image Text:**Marble Probabilities and Number Guessing Game: Understanding Probability** 1. **Marble Probability Question 1: Replacement Scenario** A bag contains 8 *yellow* marbles, 7 *white* marbles, and 6 *green* marbles. - **Question:** If one marble is drawn from the bag and then replaced, what is the probability of drawing a *yellow* marble and then a *green* marble? - **Explanation:** For this scenario, calculate the probability of two independent events: drawing a yellow marble and then a green marble. Since the marble is replaced between draws, each draw is independent. \[ P(yellow) = \frac{8}{21} \] \[ P(green) = \frac{6}{21} \] \[ P(yellow \text{ then } green) = P(yellow) \times P(green) = \frac{8}{21} \times \frac{6}{21} \] 2. **Number Guessing Game: Range Probability** - **Scenario:** In a number guessing game, a person guesses a number from 1 to 10. - **Question:** What is the probability their guess will be less than 9? - **Explanation:** Calculate the probability of guessing numbers 1 through 8. \[ P(<9) = \frac{8}{10} = \frac{4}{5} \] 3. **Marble Probability Question 2: Without Replacement Scenario** A bag contains 7 *red* marbles, 6 *green* marbles, and 8 *white* marbles. - **Question:** If one marble is drawn from the bag but not replaced, what is the probability of drawing a *red* marble and then a *white* marble? - **Explanation:** For this scenario, calculate the probability of two dependent events: drawing a red marble and then a white marble, with no replacement in between. \[ P(red) = \frac{7}{21} \] After one red marble is drawn, the total number of marbles is 20. \[ P(white | red) = \frac{8}{20} \] \[ P(red \text{ then } white) = P(red) \times P(white | red
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Similar questions
Recommended textbooks for you
A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
A First Course in Probability
A First Course in Probability
Probability
ISBN:
9780321794772
Author:
Sheldon Ross
Publisher:
PEARSON