A bag contains 3 nickels, 5 dimes, and 4 quarters. If you draw 3 coins at random from the bag, without replacement, what is the probability that you will get a nickel N, a quarter Q, and a nickel N, in that order? O. Pr(N first second third): Pr(N first Pr(N first Pr(N first Pr(N first 240 second n N third) = 216 36 1 second n N third) = 110 second / N third) = second third) - 72 =
A bag contains 3 nickels, 5 dimes, and 4 quarters. If you draw 3 coins at random from the bag, without replacement, what is the probability that you will get a nickel N, a quarter Q, and a nickel N, in that order? O. Pr(N first second third): Pr(N first Pr(N first Pr(N first Pr(N first 240 second n N third) = 216 36 1 second n N third) = 110 second / N third) = second third) - 72 =
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:A bag contains 3 nickels, 5 dimes, and 4 quarters. If you draw 3 coins at random from the bag, without
replacement, what is the probability that you will get a nickel N, a quarter Q, and a nickel N, in that order?
O.
O
Pr(N first second n N third) = 240
Pr(N first
Pr(N first
Pr(N first
Pr(N first
216
second third) = 216
1
second ʼn N third) = ` 110
$15
second / N third) :
second / N third) = 72
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