(a) (b) (c) Design a single digit BCD counter using the FSM design approach and select the correct next state (N3, N2, N1, No) and output functions (03, 02, 01, 00). Note: you can assume the BCD counter counts repeatedly from 0000 to 1001, starting at 0000. The current state is named as S3, S2, S1, So. N3=53S2S1S0 + S3525150 N2=53S0 (S2 S1) + S3S250 N₁ = 53(S₁S0) No=53525150+ S3S2S150 + S3S2S150 + S3525150 = = 03 S3, O2 S2, O1 = S1, 00 So N³ = ѳS₂S₁Sα + S3S25150 N2=53S0 (S2 S₁) + 53 S250 N₁ = 53(S₁S0) No=53525150 + S3S₂S₁50 + S3S₂S₁50 + S3S₂S₁50 + S³Ñ25150 = O3 S3, O2 S2, O1 = S1, 00 = So - N3=53S2S1S0 N2=53S0 (S2 S1) + 53S250 N₁ = 53 (S₁S0) No=S3S2S150+ S3S₂S₁S。 + S3S₂S₁S₁ + S³S₂S₁S₁ + S3S₂S150 = = O3 S3, O2 S2, O1 = S1, 00 = So N3=53S2S1S0 + S3525150 (d) = N2 S3S0 (S2 S1) + 53S250 So) (e) N₁ = 53 (S₁ No=53525150 +5352S150 + S3S25150 +53S2S150 = = O3 S3, O2 S2, O1 = S1, 00 = So None of the above

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(a)
(b)
(c)
Design a single digit BCD counter using the FSM design approach and select the
correct next state (N3, N2, N1, No) and output functions (03, 02, 01, 00).
Note: you can assume the BCD counter counts repeatedly from 0000 to 1001, starting
at 0000. The current state is named as S3, S2, S1, So.
N3=53S2S1S0 + S3525150
N2=53S0 (S2 S1) + S3S250
N₁ = 53(S₁S0)
No=53525150+ S3S2S150 + S3S2S150 + S3525150
=
=
03 S3, O2 S2, O1 = S1, 00 So
N³ = ѳS₂S₁Sα + S3S25150
N2=53S0 (S2 S₁) + 53 S250
N₁ = 53(S₁S0)
No=53525150 + S3S₂S₁50 + S3S₂S₁50 + S3S₂S₁50 + S³Ñ25150
=
O3 S3, O2 S2, O1 = S1, 00 = So
-
N3=53S2S1S0
N2=53S0 (S2 S1) + 53S250
N₁ = 53 (S₁S0)
No=S3S2S150+ S3S₂S₁S。 + S3S₂S₁S₁ + S³S₂S₁S₁ + S3S₂S150
=
=
O3 S3, O2 S2, O1 = S1, 00 = So
N3=53S2S1S0 + S3525150
(d)
=
N2 S3S0 (S2
S1) + 53S250
So)
(e)
N₁ = 53 (S₁
No=53525150 +5352S150 + S3S25150 +53S2S150
=
=
O3 S3, O2 S2, O1 = S1, 00 = So
None of the above
Transcribed Image Text:(a) (b) (c) Design a single digit BCD counter using the FSM design approach and select the correct next state (N3, N2, N1, No) and output functions (03, 02, 01, 00). Note: you can assume the BCD counter counts repeatedly from 0000 to 1001, starting at 0000. The current state is named as S3, S2, S1, So. N3=53S2S1S0 + S3525150 N2=53S0 (S2 S1) + S3S250 N₁ = 53(S₁S0) No=53525150+ S3S2S150 + S3S2S150 + S3525150 = = 03 S3, O2 S2, O1 = S1, 00 So N³ = ѳS₂S₁Sα + S3S25150 N2=53S0 (S2 S₁) + 53 S250 N₁ = 53(S₁S0) No=53525150 + S3S₂S₁50 + S3S₂S₁50 + S3S₂S₁50 + S³Ñ25150 = O3 S3, O2 S2, O1 = S1, 00 = So - N3=53S2S1S0 N2=53S0 (S2 S1) + 53S250 N₁ = 53 (S₁S0) No=S3S2S150+ S3S₂S₁S。 + S3S₂S₁S₁ + S³S₂S₁S₁ + S3S₂S150 = = O3 S3, O2 S2, O1 = S1, 00 = So N3=53S2S1S0 + S3525150 (d) = N2 S3S0 (S2 S1) + 53S250 So) (e) N₁ = 53 (S₁ No=53525150 +5352S150 + S3S25150 +53S2S150 = = O3 S3, O2 S2, O1 = S1, 00 = So None of the above
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