(a) As an iterated integral, A = B = C = Suppose R is the triangle with vertices (-1,0), (0, 1), and (1,0). [ (3x + (3x + 6y)² dA= R D = B D 1A = √₁² √² (3x (3x + 6y)² dx dy with limits of integration (b) Evaluate the integral in part (a). Hint: substitution may make the integral easier. Integral =

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Suppose \( R \) is the triangle with vertices \((-1, 0)\), \( (0, 1) \), and \( (1, 0) \).

(a) As an iterated integral, 

\[
\iint_R (3x + 6y)^2 \, dA = \int_A^B \int_C^D (3x + 6y)^2 \, dx \, dy 
\]

with limits of integration

- \( A = \text{ } \)
- \( B = \text{ } \)
- \( C = \text{ } \)
- \( D = \text{ } \)

(b) Evaluate the integral in part (a). Hint: substitution may make the integral easier.

Integral = \(\text{ }\)
Transcribed Image Text:Suppose \( R \) is the triangle with vertices \((-1, 0)\), \( (0, 1) \), and \( (1, 0) \). (a) As an iterated integral, \[ \iint_R (3x + 6y)^2 \, dA = \int_A^B \int_C^D (3x + 6y)^2 \, dx \, dy \] with limits of integration - \( A = \text{ } \) - \( B = \text{ } \) - \( C = \text{ } \) - \( D = \text{ } \) (b) Evaluate the integral in part (a). Hint: substitution may make the integral easier. Integral = \(\text{ }\)
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