A and B are playing a badminton match with the agreement that winner of each set will get 1 point and the loser 0 point. The match ends as soon as one of them is ahead by 2 points or number of 1 and sets reaches six. It is supposed that the probabilities of A and B winning a set are 3 respectively and each set is independent. Let Xi denotes the event that atleast i sets are played and Y and Z denotes the event that match has won by A and B respectively then Identify incorrect option -

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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A and B are playing a badminton match with the agreement that winner of each set will get 1 point
and the loser 0 point. The match ends as soon as one of them is ahead by 2 points or number of
sets reaches six. It is supposed that the probabilities of A and B winning a set are
and
3
respectively and each set is independent. Let X₁ denotes the event that atleast i sets are played
and Y and Z denotes the event that match has won by A and B respectively then Identify incorrect
option -
Y
(A) P(X) =
4
9
(C) P(X2k-1)= P(X2k) ke {1, 2, 3}
(B) P
(D) P
Z
X₁₂
=
=
13
81
64
729
Transcribed Image Text:A and B are playing a badminton match with the agreement that winner of each set will get 1 point and the loser 0 point. The match ends as soon as one of them is ahead by 2 points or number of sets reaches six. It is supposed that the probabilities of A and B winning a set are and 3 respectively and each set is independent. Let X₁ denotes the event that atleast i sets are played and Y and Z denotes the event that match has won by A and B respectively then Identify incorrect option - Y (A) P(X) = 4 9 (C) P(X2k-1)= P(X2k) ke {1, 2, 3} (B) P (D) P Z X₁₂ = = 13 81 64 729
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