(a) An (B-C)= (A-C) nB (b) A (B-C) = (A - B) - C (c) (A-B) U (B-A) = (ANB) (d) (A-B)U(B-A) = AUB (e) ((A-B)UCU(AUB)) UB=U, where U is the Universal set. (f) ((ANB)u(ANB))n((BNB) -A) = 0 Solution: The equation is true. We will show this using set identities. ((ANB) u (ANB)) n ((BNB) -A) (An (BUB))n((BnB) nÃ) (An (BUB))n((BUB) NA) (ANU)n(UNA) AnÃ 0 Distributive Law, Difference Equivalence De Morgan's Law, Complementation Law Complement Law (Law of Excluded Middle) (twice) Identity (twice) Complement Law (Contradiction)

(a) An (B-C)= (A-C) nB (b) A (B-C) = (A - B) - C (c) (A-B) U (B-A) = (ANB) (d) (A-B)U(B-A) = AUB (e) ((A-B)UCU(AUB)) UB=U, where U is the Universal set. (f) ((ANB)u(ANB))n((BNB) -A) = 0 Solution: The equation is true. We will show this using set identities. ((ANB) u (ANB)) n ((BNB) -A) (An (BUB))n((BnB) nÃ) (An (BUB))n((BUB) NA) (ANU)n(UNA) AnÃ 0 Distributive Law, Difference Equivalence De Morgan's Law, Complementation Law Complement Law (Law of Excluded Middle) (twice) Identity (twice) Complement Law (Contradiction)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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