Light Conditions WeatherDaylightDark, but LightedDarkDawn/DuskOther Normal14,30758758151118365 Rain875497681878 Snow/Sleet21951156172 Other12554220409 Unknown81025554871133 The following data represent the number of drivers involved in a fatal crash in 2016 in various light and weather conditions. Complete parts (a) through (c) below.Click the icon to view the data for fatal crashes in 2016.C(a) Among fatal crashes in snow/sleet, what is the probability that a randomly selected fatal crash occurs when it is daylight?The probability that a randomly selected fatal crash in snow/sleet occurs when it is daylight is approximately.(Round to three decimal places as needed.)(b) Among fatal crashes when it is daylight, what is the probability that a randomly selected fatal crash occurs in snow/sleet?The probability that a randomly selected fatal crash when it is daylight occurs in snow/sleet is approximately. (Round to three decimal places as needed.)(c) is the dark (without light) more dangerous in normal weather or in rain? Explain. Choose the correct choice below.O A. The dark is more dangerous in normal weather because the conditional probability of a fatal crash in normal weather is less than that of a fatal crash in rain.O B. The dark is more dangerous in rain because the conditional probability of a fatal crash in rain is less than that of a fatal crash in normal weather.O C. The dark is more dangerous in rain because the conditional probability f a fatal crash in rain is greater than that of a fatal crash in normal weather.O D. The dark is more dangerous in normal weather because the conditional probability of a fatal crash in normal weather is greater than that of a fatal crash in rain.OPANext3:21

Answered: (a) Among fatal crashes in snow/sleet,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The numbers 3'2, 5'8, 7'9 and 4 5 have frequencies x, (x+2), (x- 3) and (x+6) respectively. If the arithmetic mean is 4 876, find the value of x.
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141% v Zoom Add Page Insert Table Chart Text Shape Media Comment Collaborate Format Document 13! 6227020800 14! 87178291200 This document has missing fonts. Show 15! 1307674368000 16! 20922789888000 17! 355687428096000 18! 6402373705728000 19! 121645100408832000 20! 2432902008176640000 2) After a recent bank robbery, three eyewitnesses reported seeing a man with glasses flee the scene. The police suspect Ricky and make up an identity parade of five men with glasses. Ricky takes his place in the parade alongside four randomly chosen stooges. Two of the eyewitnesses identify Ricky and the third points to one of the stooges. What's the probability that Ricky would have been chosen by two of the three eyewitnesses if each witness had chosen completely at random? Solve this problem using the Binomial Probability Mass Function. (Tip: This problem will be easier to solve if you first find p, the probability of success on any one trial; in other words, the probability of a single eyewitness…
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	Light Conditions
Weather	Daylight	Dark, but Lighted	Dark	Dawn/Dusk	Other
Normal	14,307	5875	8151	1183	65
Rain	875	497	681	87	8
Snow/Sleet	219	51	156	17	2
Other	125	54	220	40	9
Unknown	810	255	548	71	133