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- A study is being carried out in the operating room of the Regional Hospital of Veraguas to establish whether the type of surgery influences the appearance of nosocomial infections in obese patients who underwent a tubular gastrectomy. The 80 patients in the study are divided into two groups, one of whom had had an open surgery (44 patients) and the others a clean surgery. There were 37 patients with infection from open surgery and 14 with infection from clean surgery. If you did not have a nosocomial infection, what is the probability that you had clean surgery? What is the probability that a patient will have clean surgery? What is the probability that a patient will have open surgery? What is the probability of clean surgery or nosocomial infection? What is the probability of no nosocomial infection or clean surgery? If you had clean surgery, what is the probability of a nosocomial infection? If you had clean surgery, what is the probability of no nosocomial infection? If you had…V Based on advancements in drug therapy, a pharmaceutical company is developing Resithan, a new treatment for depression. A medical researcher for the company is studying the effectiveness of Resithan as compared to their existing drug, Exemor. A random sample of 414 depressed individuals is selected and treated with Resithan, and 191 find relief from their depression. A random sample of 557 depressed individuals is independently selected from the first sample and treated with Exemor, and 213 find relief from their depression. Based on the medical researcher's study can we conclude, at the 0.05 level of significance, that the proportion p₁ of all depressed individuals taking Resithan who find relief from depression is greater than the proportion p₂ of all depressed individuals taking Exemor who find relief from depression? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in…A social psychologist studying mass communication randomly assigned 77 volunteers to one of two experimental groups. Fifty-seven were instructed to get their news for a month only from television, and 20 were instructed to get their news for a month only from the Internet. After the month was up, all participants were tested on their knowledge of several political issues. The researcher simply predicted that there is some kind of difference. These were the results of the study. TV group: Mty = 22, S, = 2; Internet group: M, = 26.2, s = 3. The pooled variance, rounded to four decimal places, is 2.2533. Complete parts (a) and (b) below. (a) Figure the estimated effect size for this study. Let the TV group be sample 1 and let the Internet group be sample 2. The estimated effect size for this study is
- A study was conducted to determine whether a woman's risk of transmitting HIV to her unborn child is different for the younger vs. the older the child. A sample of 100 HIV- infected women who gave birth to two children found that, when only one of the two siblings had HIV, it occurred in 7 of the 100 older siblings and in 15 of the younger siblings, as shown in the table below. Younger sibling HIV? Yes No Yes 7 Older sibling HIV? No 15 76 (a) We are not interested in the case when both siblings are HIV positive or the case when both are not HIV positive. We are only interested in the two cases in which one sibling is HIV positive and the other is not (the 7 and 15). Test Ho: the probability of being HIV positive is the same for older siblings as it is for younger siblings along with the alternative HA: the probabilities are different. Use a = .10. (b) Test the hypothesis if HA is directional, that the younger sibling (15 in the table) is more likely than the older sibling to have HIV.…A research wants to determine if pre-natal exposure to the hormones in birth control pills alters the sex makeup of midshipman fish populations (which are typically half male and half female).Specifically, the researcher wishes to test the hypothesis that exposure to hormones will increase the number of females in the population.The researcher exposes a group of pregnant midshipman fish to birth control hormones and records the sex of the first 19 offspring birthed.They then observe that 13 are female.Use a sign test to test the indicated hypothesis.What is the obtained value?An online clothing retailer is testing a new e-mail campaign by sending one version of the e-mail with the word “free” in the subject line (version A) to a group of 1,500 customers and another version of the e-mail with word “discount” in the subject line (version B) to a different group of 1500 customers. After tracking the responses to the two versions of the e-mail advertising, the retailer finds that 75 responded to version A and 105 responded to version B. At 0.05 significance level, can it be concluded that the response rate for version B is higher than the response rate to version A What is your decision? Enter “R” if your decision is to reject the null hypotheses. Enter “F” if the decision is fail to/do not reject the null hypotheses. Your answer (R/F) is: Which of the followings is the most appropriate conclusion for the hypotheses test? Enter the number corresponding to the most appropriate conclusion in the answer box. For example, if statement number 2 is the most…
- You may need to use the appropriate appendix table or technology to answer this question. In a recent poll six hundred adults were asked a series of questions about the state of the economy and their children's future. One question was, "do you expect your children to have a better life than you have had, a worse life, or a life about the same as yours?" Suppose the responses showed 251 better, 303 worse, and 46 about the same. Use the sign test and a = 0.05 to determine whether there is a difference between the number of adults who feel their children will have a better life compared to a worse life. State the null and alternative hypotheses. (Let p = the proportion of adults who feel their children will have a better life.) OH: P≥ 0.50 H₂: P 0.50 O H₂: P = 0.50 H₂: P = 0.50 O Ho: P < 0.50 H₂: P = 0.50 Find the value of the test statistic. (Round your answer to two decimal places.) z = -2.21 x Find the p-value. (Round your answer to four decimal places.) p-value = 0.0192 X What is…A research wants to determine if pre-natal exposure to the hormones in birth control pills alters the sex makeup of midshipman fish populations (which are typically half male and half female).Specifically, the researcher wishes to test the hypothesis that exposure to hormones will increase the number of females in the population.The researcher exposes a group of pregnant midshipman fish to birth control hormones and records the sex of the first 13 offspring birthed.They then observe that 11 are female.Use a sign test and a alpha of .05 to test the indicated hypothesis.What is the critical value?We know that SARS-CoV-2 was circulating, perhaps widely, in southern California as early as the beginning of February 2020. Many cases, particularly in young people, are mild or even asymptomatic. Health clinics now provide antibody tests, which are tests for whether your immune system has previously been exposed to the SARS-CoV-2 virus and recovered. People who have these antibodies may have immunity to future exposure. Which of the following is/are synonymous with P(COVID-19)? a. Prevalence b. Specificity c. 1 - Specificity d. Sensitivity
