(a) Air, n₁ = 1 Input ray, parallel to base α Glass, n₂ = 1.5
Q: & critical angle t
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A: Given ng = 1.54 yg = 32 mm ya = 25.6 mm ϕ = 400 na = 1.00 To find out ∆x = d1 + d2
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A: Given:
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A: From Snell's law, n1n2=sinθvsinθsinθv=sinθn1n2sinθv=sin45°×11.336θv=31.96°
Q: is transmitted?
A: E=(e→x2+32e→y+e→z)cos(ωt−k→.r→)k=−32e→x+12e→yAir glass incident normal is in y direction.TE wave…
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- Q. 1. (i) Monochromatic light of wavelength 589 nm is incident from air on a water surface. If u for water is 1.33, find the wavelength, frequency and speed of the refracted light. (ii) A double convex lens is made of a glass of refractive index 1.55, with both faces of the same radius of curvature. Find the radius of curvature required, if the focal length is 20 cm.(b) How does the index of refraction relate to the speed of light in a medium? If the index of refraction of water is 1.33, calculate the speed of light in water. Give one application of total internal reflection.A plane sound wave in air at 20°C, with wavelength 589 mm, is incident on a smooth surface of water at 25°C at an angle of incidence of 12.3°. (a) Determine the angle of refraction for the sound wave. (b). Determine, the wavelength of the sound in water. Enter a number with units. A narrow beam of sodium yellow light, with wavelength 589 nm in vacuum, is incident from air onto a smooth water surface at an angle of incidence of 12.3o. (c) Determine the angle of refraction. (d) Determine the wavelength of the light in water.
- Building contractors often install double-glazed windows to prevent thermal energy (heat) from entering or exiting a building. In addition to being effective insulators, such windows present interesting optical effects. 62.0 mm In the figure, a double-glazed window consists of two identical of glass (ng panes 1.54), each yg thick, separated by an air gap of ya = 49.6 mm. Use na = 1.00 for the index of refraction of air. = If light incident on the glass makes an angle of = 40.00° with respect to the glass, find the shift in path Ax as the light enters the room. Ax = 42.36 Incorrect glass air glass mmA uniaxial crystal with refractive indices no and ne is cut so that the optic axis is perpendicular to the surface as shown in the diagram. Show that for a beam incident on the interface from air at an angle of incidence, 0; that the angle of refraction of the extraordinary e – wave is sin(0;) ne tan(0.) No Vn? – sin?(0;) optic axis direction Or, OeAn optical fiber has an index of refraction n and diameter d. It is surrounded by vacuum. Light is sent into the fiber along its axis as shown. (a) Find the smallest outside radius Rmin permitted for a bend in the fiber if no light is to escape. (b) What If? What result does part (a) predict as d approaches zero? Is this behavior reasonable? Explain. (c) As n increases? (d) As n approaches 1? (e) Evaluate Rmin assuming the fiber diameter is 100 mm and its index of refraction is 1.40.