(a) According to the right-hand rule for currents in a magnetic field, since the current is to the south, the to make the magnetic force vector point upward. magnetic field must be to the east ♥ W- B = IL F₁ = IL XB B N (b) With I to the south and B pointing east, the force on the wire is FB = ILB sin 0, which must counterbalance the weight mg of the wire. So we have the following. 1.25 E FB mg 22=m² = (²) (7) IL IL (9.80 m/s²) A) ( А .47 102 cm/m 103 g/kg /cm) (10²3 0.3 Your response differs from the correct answer by more than 10%. Double check your calculations. T
(a) According to the right-hand rule for currents in a magnetic field, since the current is to the south, the to make the magnetic force vector point upward. magnetic field must be to the east ♥ W- B = IL F₁ = IL XB B N (b) With I to the south and B pointing east, the force on the wire is FB = ILB sin 0, which must counterbalance the weight mg of the wire. So we have the following. 1.25 E FB mg 22=m² = (²) (7) IL IL (9.80 m/s²) A) ( А .47 102 cm/m 103 g/kg /cm) (10²3 0.3 Your response differs from the correct answer by more than 10%. Double check your calculations. T
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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
Transcribed Image Text:(a) According to the right-hand rule for currents in a magnetic field, since the current is to the south, the
to make the magnetic force vector point upward.
magnetic field must be to the east
B =
=
N
W
A
IL
(b) With I to the south and B pointing east, the force on the wire is FB = ILB sin 0, which must counterbalance
the weight mg of the wire. So we have the following.
(7)(77)
FB
IL
F. - IL XB
B
=
1.25
mg
IL
E
=
9.80 m/s²)
A
.47
10² cm/m
10³ g/kg
g/cm
(cm) (1023
0.3
X
Your response differs from the correct answer by more than 10%. Double check your calculations. T
We have found the field to just balance the force of gravity. Any increase of this magnetic field, no matter how
small, would lift the wire.
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