(a) A positively-charged block, initially at rest, moves up an incline that has friction. Represent this process using a work-energy bar chart and the work-energy (b) A negatively-charged ball, initially at rest, falls until it is stopped by compressing a spring. The spring rests on a positively-charged plate that produces a steadily decreasing potential with increasing distance above it. Represent this process using a work-energy bar chart and the work-energy equation. Initial Final position position v>0 Initial Situation Final SituetiOn m ta

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Chapter1: Units, Trigonometry. And Vectors
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(a) A positively-charged block, initially at rest, moves up
an incline that has friction. Represent this process
using a work-energy bar chart and the work-energy
(b) A negatively-charged ball, initially
at rest, falls until it is stopped by
compressing a spring. The spring
rests on a positively-charged plate
that produces a steadily decreasing
potential with increasing distance
above it. Represent this process
using a work-energy bar chart and
the work-energy equation.
Initial
Final
position
position
v>0
Initial Situation
Final SituetiOn
m ta
Transcribed Image Text:(a) A positively-charged block, initially at rest, moves up an incline that has friction. Represent this process using a work-energy bar chart and the work-energy (b) A negatively-charged ball, initially at rest, falls until it is stopped by compressing a spring. The spring rests on a positively-charged plate that produces a steadily decreasing potential with increasing distance above it. Represent this process using a work-energy bar chart and the work-energy equation. Initial Final position position v>0 Initial Situation Final SituetiOn m ta
Expert Solution
Step 1

(a)

The charge (q) of mass (m) faces no elastic or electrostatic potential energy in this system.

Hence, the Us and Uq terms are zero initially and finally.

Since it starts from rest at the ground position, K0 and Ug0 are zero.

Friction (f) and some external force (F) act on the charge to contribute to the work (W), which is the only non-zero quantity on left.

At the final position, it has non zero and positive K, Ug, and ΔUint due to friction.

The height of the W bar must equal the sum of the heights of the K, Ug, and ΔUint bars as per energy conservation.

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