(a) A function f (x) is given as 1 x<0 2 f(x)=• xe x>0 2x Evaluate lim f(x) numerically by constructing a table. (b) Given for x<2 f (x) = -x+6 for x22 Sketch the graph for f(x). Hence, find i) lim f(x) ii) lim f(x) X+ 2* SEM II 202

Q: If f(x) = (1+%) 3 ) 6x *", find lim f(x).

A: We have to find limx→∞fx when fx=1+3x6x If we put limit value then we get that it is 1∞ form We know…

Q: * +3 ,x1 „x>1 g(x) exists? Justify. 1+1 f(x) a) Does lim f(x) + g(x) exists? Justify. b) Does lim

A: Solve the given function

Q: d. lim x_1 x-1

A: Since there are multiple questions so according to guidelines we can solve only first one.

Q: F(x) = {e^ X-3 OLX Find lim F(x) x 70 im f(x) x 70

A:

Q: In the above space, draw the graph of a function with ALL of the following properties: (a) f(0) =…

A: The conditions given for the function is : a) f(0)=-2 i.e. the curve passes through the point…

Q: Difference between f(c) and lim f(x) as x approaches c

A: Consider a function fx. The lim f(x) as x approaches to c is said to exist when the right hand limit…

Q: I) Graph of f(x) is given on the right. Answer the following questions using the graph. a) lim f(x)=…

A: Given: The graph of function fx as, To find: (a)limx→-2+fx (b)limx→-2-fx (c)limx→-2fx (d)f2…

Q: Find lim f(x) if f (x) = 3Vx + 2 x 2 %3D X-2 Determine the intervals where the function given in…

A: Given f(x=3x+2x&lt;2x2+2x≥2

Q: [1/(2+x)]-(1/2). Find lim X-0 4 O 2 4 O -2

A:

Q: (a) f(1) (b) lim f(x) (c) f(4) (d) lim f(x)

A: (a) From the graph of the function, The value of the function at 1 f1 is 3.   Thus, f1=3

Q: Let f(x): = |x-1| x-1 Please follow the same instructions as in #1. 2.(a) f(1) 2.(b) lim f(x) X→-80…

A:

Q: Write an example of a function f that satisfies lim f(x) = 2 X→1 x-1

A: Limit.

Q: Sketch the graph of a function f(x) defined for all x € R that satisfies all of the following…

A:

Q: can you show me how to do

A: We will find the limits from rhe graph.

Q: Let f(x) be the following piece wise function f(x) = ( x ² + => if 0 1 Show lim f(x) does not exist…

A: