(a) A force F = (6x1 + 5yĵ), where F is in newtons and x and y are in meters, acts on an object as the object moves in the x-direction from the origin to x = 4.80 m. Find the work W = ·/ F F. dr done by the force on the object (in J). 69.12 J /*. F. dr done by the force on the object (in J) if it moves from the origin to (4.80 m, 4.80 m) along a straight-line path making an angle of 45.0° with the positive x-axis. X J (b) What If? Find the work W = 69.12
(a) A force F = (6x1 + 5yĵ), where F is in newtons and x and y are in meters, acts on an object as the object moves in the x-direction from the origin to x = 4.80 m. Find the work W = ·/ F F. dr done by the force on the object (in J). 69.12 J /*. F. dr done by the force on the object (in J) if it moves from the origin to (4.80 m, 4.80 m) along a straight-line path making an angle of 45.0° with the positive x-axis. X J (b) What If? Find the work W = 69.12
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:**Problem: Work Done by a Force**
(a) A force \(\mathbf{F} = (6x \hat{\mathbf{i}} + 5y \hat{\mathbf{j}})\), where \(\mathbf{F}\) is in newtons and \(x\) and \(y\) are in meters, acts on an object as the object moves in the x-direction from the origin to \(x = 4.80\, \text{m}\). Find the work \(W = \int \mathbf{F} \cdot d\mathbf{r}\) done by the force on the object (in Joules).
- **Solution:**
- Answer: \(\boxed{69.12 \, \text{J}}\)
(b) **What If?** Find the work \(W = \int \mathbf{F} \cdot d\mathbf{r}\) done by the force on the object (in Joules) if it moves from the origin to \((4.80 \, \text{m}, 4.80 \, \text{m})\) along a straight-line path making an angle of \(45.0^\circ\) with the positive x-axis.
- **Solution:**
- User provided answer: \(\boxed{69.12} \, \text{(Incorrect)}\)
Note: Consider breaking the force into components corresponding to the direction of movement for accurate calculations.
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