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a) A current carrying wire is placed in an external magnetic field produced by a toroid with an air gap. The steel ring (u=3000) has a square cross-sectional area of 6x10* m², it has a total length of 0.45 m with a 0.05 m air gap. It is wound with a coil of 200 turns that carries 3.5 A of current. i) Calculate the flux in the circuit. ii) Calculate the magnetic field strength in the air gap. iii) The magnetic field direction is clockwise and the air gap is on left hand side of the toroid, calculate the force exerted on the wire if a current of 2 A is flowing through it, and draw a diagram to show the direction the force will be exerted in.

a) A current carrying wire is placed in an external magnetic field produced by a toroid with an air gap. The steel ring (u=3000) has a square cross-sectional area of 6x10* m², it has a total length of 0.45 m with a 0.05 m air gap. It is wound with a coil of 200 turns that carries 3.5 A of current. i) Calculate the flux in the circuit. ii) Calculate the magnetic field strength in the air gap. iii) The magnetic field direction is clockwise and the air gap is on left hand side of the toroid, calculate the force exerted on the wire if a current of 2 A is flowing through it, and draw a diagram to show the direction the force will be exerted in.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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a) A current carrying wire is placed in an external magnetic field produced by a toroid with an air gap. The steel ring (4,=3000) has a square cross-sectional area of 6x10“ m², it has a total length of 0.45 m with a 0.05 m air gap. It is wound with a coil of 200 turns that carries 3.5 A of current. i) Calculate the flux in the circuit. ii) Calculate the magnetic field strength in the air gap. iii) The magnetic field direction is clockwise and the air gap is on left hand side of the toroid, calculate the force exerted on the wire if a current of 2 A is flowing through it, and draw a diagram to show the direction the force will be exerted in.
Transcribed Image Text:a) A current carrying wire is placed in an external magnetic field produced by a toroid with an air gap. The steel ring (4,=3000) has a square cross-sectional area of 6x10“ m², it has a total length of 0.45 m with a 0.05 m air gap. It is wound with a coil of 200 turns that carries 3.5 A of current. i) Calculate the flux in the circuit. ii) Calculate the magnetic field strength in the air gap. iii) The magnetic field direction is clockwise and the air gap is on left hand side of the toroid, calculate the force exerted on the wire if a current of 2 A is flowing through it, and draw a diagram to show the direction the force will be exerted in.
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