a) A compound with two double bonds, one cis and one trans; molecular formula C6H10. b) A tri-substituted benzene ring with molecular formula C7H;C1O. c) A compound with both a 2° alcohol and an aldehyde, molecular formula C,H12O2, that could form a cyclic hemiacetal. d) The cyclic hemiacetal formed by 1c) (No name required.) e) A 2° ammonium salt with molecular formula C4H12NCI.
a) A compound with two double bonds, one cis and one trans; molecular formula C6H10. b) A tri-substituted benzene ring with molecular formula C7H;C1O. c) A compound with both a 2° alcohol and an aldehyde, molecular formula C,H12O2, that could form a cyclic hemiacetal. d) The cyclic hemiacetal formed by 1c) (No name required.) e) A 2° ammonium salt with molecular formula C4H12NCI.
Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Chapter13: Alcohols, Phenols, And Ethers
Section: Chapter Questions
Problem 13.72E
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For each of the following, draw a structural formula that meets the stated requirements, then name each structureyour drew (unless otherwise indicated) according to either IUPAC or common nomenclature.

Transcribed Image Text:a) A compound with two double bonds, one cis and one trans; molecular formula C6H10.
b) A tri-substituted benzene ring with molecular formula C7H¬CIO.
c) A compound with both a 2° alcohol and an aldehyde, molecular formula C,H1202, that
could form a cyclic hemiacetal.
d) The cyclic hemiacetal formed by 1c) (No name required.)
e) A 2° ammonium salt with molecular formula C4H12NCI.
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