a) A box of mass, m, slides down an inclined plane that makes an angle 0 with the horizontal as shown in Figure 1. Find a differential equation for the velocity v(t) of the box at time t in each of the following three cases: i. No sliding friction and no air resistance. ii. With sliding friction and no air resistance. jii. With sliding friction and air resistance.

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Chapter1: Units, Trigonometry. And Vectors
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4 a)

i

ii

iii

4. (a) A box of mass, m, slides down an inclined plane that makes an angle 0 with
the horizontal as shown in Figure 1. Find a differential equation for the
velocity v(t) of the box at time t in each of the following three cases:
i. No sliding friction and no air resistance.
ii. With sliding friction and no air resistance.
iii. With sliding friction and air resistance.
In cases (ii) and (iii), use the fact that the force of friction opposing the
motion of the box is µN, where u is the coefficient of sliding friction
and N is the normal component of the weight of the box. In case (iii)
assume that air resistance is proportional to the instantaneous velocity.
friction
motion
-W = mg |50
Figure 1: Question 4
(b) In part (a), suppose that the box weighs 412 kg.m/s², acceleration due to
gravity is taken to be 9.81 m/s², the angle of inclination of the plane is
0 = 30, the coefficient of sliding friction is µ = v3/4, and the additional
retarding force due to air resistance is numerically equal to u. Solve the
differential equation in each of the three cases, assuming that the box starts
at rest from the highest point 50 metres above ground.
Transcribed Image Text:4. (a) A box of mass, m, slides down an inclined plane that makes an angle 0 with the horizontal as shown in Figure 1. Find a differential equation for the velocity v(t) of the box at time t in each of the following three cases: i. No sliding friction and no air resistance. ii. With sliding friction and no air resistance. iii. With sliding friction and air resistance. In cases (ii) and (iii), use the fact that the force of friction opposing the motion of the box is µN, where u is the coefficient of sliding friction and N is the normal component of the weight of the box. In case (iii) assume that air resistance is proportional to the instantaneous velocity. friction motion -W = mg |50 Figure 1: Question 4 (b) In part (a), suppose that the box weighs 412 kg.m/s², acceleration due to gravity is taken to be 9.81 m/s², the angle of inclination of the plane is 0 = 30, the coefficient of sliding friction is µ = v3/4, and the additional retarding force due to air resistance is numerically equal to u. Solve the differential equation in each of the three cases, assuming that the box starts at rest from the highest point 50 metres above ground.
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