(a) A 25.0 mL sample of 0.175 M methylamine CH3NH2 (Kb = 1.3 x 10-5) is titrated with 0.150 M HBr. Find the initial pH at the ½ equivalence point after 5.0 mL of acid is added the pH at the equivalence point the pH after 5.0 mL acid is added after the equivalence point
(a) A 25.0 mL sample of 0.175 M methylamine CH3NH2 (Kb = 1.3 x 10-5) is titrated with 0.150 M HBr. Find the initial pH at the ½ equivalence point after 5.0 mL of acid is added the pH at the equivalence point the pH after 5.0 mL acid is added after the equivalence point
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 45QAP: A sample of 0.220 M triethylamine, (CH3CH2)3 N, is titrated with 0.544 M HCl. (K b...
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- (a) A 25.0 mL sample of 0.175 M methylamine CH3NH2 (Kb = 1.3 x 10-5) is titrated with
0.150 M HBr.
- Find the initial pH
- at the ½ equivalence point
- after 5.0 mL of acid is added
- the pH at the equivalence point
- the pH after 5.0 mL acid is added after the equivalence point
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Step 1: Determine the given values
VIEWStep 2: Determination of initial pH
VIEWStep 3: Determination of pH at the ½ equivalence point
VIEWStep 4: Determination of pH after 5.0 mL of acid is added
VIEWStep 5: Determination of pH at the equivalence point
VIEWStep 6: Determination of pH after 5.0 mL acid is added after the equivalence point
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