A ° a 2 0 X- D AD=2 BC-8 ACEX 18 XP atl E NyS

Q: fas=30052 Find FGx) COS L %3D

A: Given Fx=3cosx, we need to find F'(x)

Q: dy dx y² + 1

A:

Q: 10. Given: CH bisects ZDHG , mGF = (2x + 6) , and mDC = (7x – 1)'. E H C G F

A:

Q: Solve ydæ %3D (е9/2 + 20у — 2л)dy - = A- B I . E E E E 8 &

A:

Q: 9. H. K m L GHK = 22,5° HG = 120° HK = 4x +3"

A:

Q: х dx е 2

A:

Q: Find the area of the indicated sector 2m 270° 1080mm2 3πm² 65 m² 200 m² 3

A:

Q: 16. m SVT 10x – 3° \60° -1 + 6x° W U 8x + 8° 17+ 7x° V

A:

Q: 00 3 .a 3. 8. 16

A: Given integration is ∫0∞x9 e-x4dx

Q: V1 + cosx dx sk. The value of k is Select one: а. b. 1 С. 1 V3

A:

Q: Sx? cosx dx

A:

Q: 3x F 5

A:

Q: +/3 •п/4 Г sec 0 p² tan 0 seco dp d0 do

A:

Q: Find dr 기 de de r = 3 sec 0 csc 0 11

A: SOLUTION-

Q: dx V1+x

A:

Q: CON C 36 45

A: Given that  Triangle ABC is a right angled triangle in which angle B is right angle AB=36  BC=27…

Q: 24 – 44 dy 2+ 49 с.

A:

Q: 00 dx x² 7/3 (Type an exact answer +49 %3D

A:

Q: 2 4r -2 Period Amplitude:

A:

Q: 0 KIN KIN π 2 2 ²/² 02 sin o dr do de 0

A:

Q: Si +dx = -2 x 2 False O True

A:

Q: 6) S dx

A: We apply substitution rule for solving the integration

Q: A 2. AC = x. BC = X. AB = 16. Find x in simplest form. В

A:

Q: 9y+14 dy 3. Jy-2)(y²++4) (y-2)(y²+4)

A:

Q: /Q27 cot? Vx dx = – csc Vx – Vĩ + c True False Leave Question

A:

Q: 3X-Y-4 2 . when X=4 i y=l

A:

Q: 1 :dx J xV16ln² x – 9

A:

Q: A B D) e22 E

A: To find  ∫1ex2-1xdx Formulae used ∫xndx=xn+1n+1∫1xdx=ln x∫abf'(x)dx=f(b)-f(a)

Q: S sec 2ydy

A: Topic:- integration

Q: 16 10 X, 700

A: