A 9.544 mol sample of krypton gas is maintained in a 0.8383 L container at 302.4 K. What is the pressure in atm calculated using the van der Waals' equation for Kr gas under these conditions? For Kr, a= 2.318 L². atm mol² and b= 0.03978 L mol Pressure = atm

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A 9.544 mol sample of krypton gas is maintained in a 0.8383 L container at 302.4 K. What is the pressure in atm calculated using the van der Waals' equation for Kr gas under these conditions? 

For Kr, \( a = 2.318 \, \frac{L^2 \cdot atm}{mol^2} \) and \( b = 0.03978 \, \frac{L}{mol} \).

**Pressure = [blank] atm**
Transcribed Image Text:A 9.544 mol sample of krypton gas is maintained in a 0.8383 L container at 302.4 K. What is the pressure in atm calculated using the van der Waals' equation for Kr gas under these conditions? For Kr, \( a = 2.318 \, \frac{L^2 \cdot atm}{mol^2} \) and \( b = 0.03978 \, \frac{L}{mol} \). **Pressure = [blank] atm**
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