A 9.055 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 16.14 grams of CO₂ and 6.608 grams of H₂O are produced. In a separate experiment, the molar mass is found to be 74.08 g/mol. Determine the empirical formula and the molecular formula of the organic compound.

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### Combustion Analysis and Molecular Formula Determination

**Problem Statement:**

A 9.055-gram sample of an organic compound containing carbon (C), hydrogen (H), and oxygen (O) is analyzed by combustion analysis. From the combustion analysis, 16.14 grams of carbon dioxide (CO₂) and 6.608 grams of water (H₂O) are produced.

In a separate experiment, the molar mass of the compound is found to be 74.08 g/mol. Determine the empirical formula and the molecular formula of the organic compound.

*(Enter the elements in the order C, H, O.)*

**Calculations Needed:**

1. **Calculating Moles of Carbon:**
    - Use the mass of CO₂ produced to find the moles of carbon.
    
2. **Calculating Moles of Hydrogen:**
    - Use the mass of H₂O produced to find the moles of hydrogen.
    
3. **Calculating Moles of Oxygen:**
    - Use the remaining mass of the sample to determine the moles of oxygen, considering the masses due to carbon and hydrogen derived from CO₂ and H₂O.
    
4. **Determining the Empirical Formula:**
    - Calculate the simplest whole number ratio of moles of C, H, and O.

5. **Determining the Molecular Formula:**
    - Use the molar mass and the empirical formula mass to find the molecular formula.

**Formulas to be Filled:**

- **Empirical Formula:**
    ```
    [ Textbox for empirical formula ]
    ```

- **Molecular Formula:**
    ```
    [ Textbox for molecular formula ]
    ```

**Additional Explanation:**

- **Empirical Formula:** This is the simplest ratio of the elements in the compound.
- **Molecular Formula:** This is the actual number of atoms of each element in a molecule of the compound, and it is a multiple of the empirical formula based on the molecular weight.

By entering the correct empirical and molecular formulas, one can identify the structure of the organic compound in question.
Transcribed Image Text:### Combustion Analysis and Molecular Formula Determination **Problem Statement:** A 9.055-gram sample of an organic compound containing carbon (C), hydrogen (H), and oxygen (O) is analyzed by combustion analysis. From the combustion analysis, 16.14 grams of carbon dioxide (CO₂) and 6.608 grams of water (H₂O) are produced. In a separate experiment, the molar mass of the compound is found to be 74.08 g/mol. Determine the empirical formula and the molecular formula of the organic compound. *(Enter the elements in the order C, H, O.)* **Calculations Needed:** 1. **Calculating Moles of Carbon:** - Use the mass of CO₂ produced to find the moles of carbon. 2. **Calculating Moles of Hydrogen:** - Use the mass of H₂O produced to find the moles of hydrogen. 3. **Calculating Moles of Oxygen:** - Use the remaining mass of the sample to determine the moles of oxygen, considering the masses due to carbon and hydrogen derived from CO₂ and H₂O. 4. **Determining the Empirical Formula:** - Calculate the simplest whole number ratio of moles of C, H, and O. 5. **Determining the Molecular Formula:** - Use the molar mass and the empirical formula mass to find the molecular formula. **Formulas to be Filled:** - **Empirical Formula:** ``` [ Textbox for empirical formula ] ``` - **Molecular Formula:** ``` [ Textbox for molecular formula ] ``` **Additional Explanation:** - **Empirical Formula:** This is the simplest ratio of the elements in the compound. - **Molecular Formula:** This is the actual number of atoms of each element in a molecule of the compound, and it is a multiple of the empirical formula based on the molecular weight. By entering the correct empirical and molecular formulas, one can identify the structure of the organic compound in question.
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