A 9.0-g bullet is shot into a 4.0-kg block, at rest on a frictionless horizontal surface (see the figure). The bullet remains lodged in the block. The block moves into an ideal massless spring and compresses it by 6.5 cm. The spring constant of the spring is 3210 N/m. (a) What was the initial velocity of the bullet? (b) How much kinetic energy was lost in the collision?

Q: A bullet having mass m and velocity v collides with a block at rest having mass M. Mass M is…

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Q: A spring with a spring constant of 301 N/m is initially compressed by a distance of 0.065 m from its…

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Q: A box is attached to a spring and at rest at the equilibrium position of the spring when a bullet…

A: When the body is placed at the surface with coefficient of friction μ, the friction force is given…

Q: A spring with a spring constant of 335 N/m is initially compressed by a distance of 0.045 m from its…

A: Given data: k = 335 N/m x= 0.045 m m=0.045 kg Need to determine the speed of the block.

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A: Since the student has requested for part B only, hence its solution is as follows :

Q: a) In terms of the variables given in the problem statement, find an equation for the speed of the…

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Q: A spring of negligible mass stretches 3.46 cm from its relaxed length when a force of 5.40 N is…

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Q: A 2.0-kg block of wood is attached to a horizontal spring that is at its equilibrium length (not…

A: As the bullet hit the wooden block there is no external force acting on bullet plus mass system so…

Q: A block of mass M = 6.10 kg, at rest on a horizontal frictionless table, is attached to a rigid…

A:

Q: A spring of negligible mass stretches 3.46 cm from its relaxed length when a force of 5.40 N is…

A: Stretch in the spring is dx=3.46 cm = 0.0346 m Applied force is F = 5.40 N Mass of the particle is m…

Q: Suppose a spring (with a spring constant of 600 N/m) is compressed 0.4 m. If a projectile of mass…

A: GivenSpring constant, K=600 N/mSpring compressed to distance, d=0.4 mMass of projectile, m=0.05 kg

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Q: A 12g bullet is fired horizontally against a 100 g wooden block resting on a rough horizontal…

A: Apply conservation of mechanical energy to block embedded bullet.…

Q: A 5.00-g bullet moving with an initial speed of v₁ = 450 m/s is fired into and passes through a…

A: Mass of bullet , m1 = 5 g = 0.005 kgMss of block , m2 = 1 kgInitial velocity of bullet , u1 = 450…

Q: An AK47 (Kalashnikov Rifle) shoots bullets that have a mass of 7.90g. The design of the AK47 rifle…

A: Mass of the bullet is m = 7.90×10-³ kg  Mass of the block is M = 7.24 kg  K = 203000 N/m…

Q: A rifle bullet with mass 8.00 gg strikes and embeds itself in a block with mass 0.992 kgkg that…

A: Analyze the following figure. 1) As per the conservation of energy, Here, the EBI and EAI…

Q: A 15.0 kg block is attached to a very light horizontal spring of force constant 425 N/m and is…

A: The final answer is attached below Explanation:

Q: A block of mass M = 5.90 kg, at rest on a horizontal frictionless table, is attached to a rigid…

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Q: A massless spring with spring constant k = 25 N/m is attached at one end of a block of mass M = 3.0…

A: spring constant (k) = 25 N/m M = 3 kg mb = 0.3 kg vo = 200 m/s

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Q: A spring with a spring constant of 303 N/m is initially compressed by a distance of 0.056 m from its…

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Q: Agent Arlene devised the following method of measuring the muzzle velocity of a rifle (the figure…

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Q: A 0.430 kg block of wood rests on a horizontal frictionless surface and is attached to a spring…

A: Using conservation of momentum, mu=m+Mvv=umm+M

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A: Solution: Given: k = force constant of spring = 850 N/m s1 = initial compression of spring = 0.075 m…

Q: 7. Two masses, m1 = 2 kg and m2 = 8 kg, are pressed onto identical springs (k = 2 × 104 N/m) so that…

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Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.