Answered: A) √9-x2 (7) According to the method of…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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$(1) log (9)+ log, (4) is equal to: B) 2 A) logo (13) (2) Solve the equation In (1) = 2: e²+1 e²+1 A) 2+1 e2-1 B) C) 1-82 (3) The solutions of e2x + ex-6=0 are: A) x = ln(2), In(3) A) -2 -8 4 (8) √3 x²+9 TT (6) Suppose that x = 3 tan 8, then cos 0 = =: √x²-9 A) √√9-x² B) C) √9+x² A) C) x = 2,-3 D) x = In (2) (4) Assume f is a differentiable function, f x³ f'(x) dx = A) x³ f(x) - fx¹ f(x) dx B)x f(x) + c C) x³ f"(x)-3 f x² f(x) dx (5) Which of the following improper integrals converge: A) x dx B)e-2x dx x dx = B) x = ln(2), In(-3) C) logo (2) (7) According to the method of partial fractions, B) C) -1 B) 4 (9) The derivative of 2 sin (2sin-¹x) In 2 A) √1-x2 2+2e -1 -1x B) C) is: 2sin 1x √1-x² D) D) 2+2e 1-e C) D) 6 √x²+9 3x (x-1)(x-2)(x-3) D)3 D) Diverges In 2 (2sin-1x) In √1+x² = D) x³ f(x)-3 f x² f(x) dx D) In (x) dx (x-1) + B (x-2) + (x-3) the value of B is D) (2 cos-¹x) In 2 √1-x²$

Transcribed Image Text:(1) log (9)+ log, (4) is equal to: B) 2 A) logo (13) (2) Solve the equation In (1) = 2: e²+1 e²+1 A) 2+1 e2-1 B) C) 1-82 (3) The solutions of e2x + ex-6=0 are: A) x = ln(2), In(3) A) -2 -8 4 (8) √3 x²+9 TT (6) Suppose that x = 3 tan 8, then cos 0 = =: √x²-9 A) √√9-x² B) C) √9+x² A) C) x = 2,-3 D) x = In (2) (4) Assume f is a differentiable function, f x³ f'(x) dx = A) x³ f(x) - fx¹ f(x) dx B)x f(x) + c C) x³ f"(x)-3 f x² f(x) dx (5) Which of the following improper integrals converge: A) x dx B)e-2x dx x dx = B) x = ln(2), In(-3) C) logo (2) (7) According to the method of partial fractions, B) C) -1 B) 4 (9) The derivative of 2 sin (2sin-¹x) In 2 A) √1-x2 2+2e -1 -1x B) C) is: 2sin 1x √1-x² D) D) 2+2e 1-e C) D) 6 √x²+9 3x (x-1)(x-2)(x-3) D)3 D) Diverges In 2 (2sin-1x) In √1+x² = D) x³ f(x)-3 f x² f(x) dx D) In (x) dx (x-1) + B (x-2) + (x-3) the value of B is D) (2 cos-¹x) In 2 √1-x²

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