A 9 400-N shark is supported by a rope attached to a 4.20-m rod that can pivot at the base.20.0°60.0°(a) Calculate the tension in the cable between the rod and the wall, assuming the cable is holding the system in the position shown in the figure. (Give you answer to three significant digits.)N(b) Find the horizontal force exerted on the base of the rod.magnitudedirection--Select--- v(c) Find the vertical force exerted on the base of the rod. Ignore the weight of the rod.magnitudedirection--Select--- v

Given: Force on shark 9400N Length of rod 4.20m To find: (a) Tension in the cable between the rod and the wall (b) Horizontal force exerted on the base of the rod (c) Vertical force exerted on the base of the rod Solution(a): Calculation: Net tension in the cable between the rod and the wall is given as:T(4.20m)sin(60°+20°)-(9400N)(4.20m)cos60°=0Finding T;4.20m(T)×sin(80°)=39480×cos60°=-37601.264T=37601.2644.174=9008.448NAnswer(a) is tension in the cable between the rod and the wall T=9008.448NSolution(b): Calculation: Net force in horizontal direction is:Rx-Tcos20°=0as T=9008.448NRx-9008.448×cos20°=0Rx=3676.186NAnswer(b) is Magnitude of Horizontal force Rx=3676.186N exerted on the base of the rod 'Horizontally'.Solution(c): Calculation: Net force in the vertical direction:Ry+Tsin20°=9400Nput T=9008.448NRy+9008.448×sin20°=9400NRy+8224.219=9400NRy=1175.781NAnswer(c) is Magnitude of force is Ry=1175.781N on the base of the rod in 'Vertical direction'.

Answered: A 9 400-N shark is supported by a rope…