**Problem Statement:**A 85.0 kg man jumps straight up (with no horizontal component of velocity) and catches a horizontally traveling ball. He catches the 0.430 kg ball exactly at the peak of his leap, which is 0.488 meters off the ground. He hits the ground 0.0282 meters away from where he leapt. When it was caught, how fast was the ball travelling?**Input Field:**- **Speed (m/s):** [__________]**Graphical Elements:**- There is a data entry field for the speed to be calculated.- **Tools Section:** Includes an option to input the answer in scientific notation with a button marked \( \times10^y \).

Given: Mass of man,mm=85kgInitial Velocity of man,um=0m/sMass of ball,mb=0.430kgHeight of the peak…

Answered: A 85.0 kg man jumps straight up (with…

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