A 8.53 g/L CH3OH B 25.9 g/L C4H₂OH Two aqueous solutions are separated by a semipermeable membrane through which only water molecules can pass, as shown in the illustration to the left. At the start of the experiment, compartment A contains a solution containing 8.53 grams per liter of the nonelectrolyte methanol (CH3OH) and compartment B contains a solution containing 25.9 grams per liter of the nonelectrolyte butanol (C4H9OH). Which of the following represents the expected appearance of the apparatus after sufficient time has passed?

Introduction to General, Organic and Biochemistry
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ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter6: Solutions And Colloids
Section: Chapter Questions
Problem 6.74P: 6-74 An osmotic semipermeable membrane that allows only water to pass separates two compartments, A...
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A
8.53 g/L
CH3OH
A
A
B
25.9 g/L
C4H₂OH
B
B
Two aqueous solutions are separated by a semipermeable membrane through which only water molecules can pass,
as shown in the illustration to the left.
At the start of the experiment, compartment A contains a solution containing 8.53 grams per liter of the
nonelectrolyte methanol (CH3OH) and compartment B contains a solution containing 25.9 grams per liter of the
nonelectrolyte butanol (C4H9OH). Which of the following represents the expected appearance of the apparatus after
sufficient time has passed?
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Transcribed Image Text:A 8.53 g/L CH3OH A A B 25.9 g/L C4H₂OH B B Two aqueous solutions are separated by a semipermeable membrane through which only water molecules can pass, as shown in the illustration to the left. At the start of the experiment, compartment A contains a solution containing 8.53 grams per liter of the nonelectrolyte methanol (CH3OH) and compartment B contains a solution containing 25.9 grams per liter of the nonelectrolyte butanol (C4H9OH). Which of the following represents the expected appearance of the apparatus after sufficient time has passed? Previous Next
Expert Solution
Step 1

Molecular weight of CH3OH = 12+(1×4)+16 = 32 g/mol

Concentration of CH3OH = 8.53 g/L32 g/mol=0.267 mol/L

 

Molecular weight of C4H9OH = (12×4)+(1×10)+16 = 74 g/mol

Concentration of C4H9OH =25.9 g/L74 g/mol=0.350 mol/L

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