A 7.80-g bullet moving at 575 m/s penetrates a tree trunk to a depth of 5.50 cm. (a) Use work and energy considerations to find the average frictional force that stops the bullet. (b) Assuming the frictional force is constant, determine how much time elapses between the moment the bullet enters the tree and the moment it stops moving.

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A: Given information:Mass of the block (m) = 4.4 kgCoefficient of friction between the block and the…

Q: A 7.80-g bullet moving at 690 m/s penetrates a tree trunk to a depth of 6.20 cm. (a) Use work and…

A: Mass of bullet (mb)=7.8 g Initial speed of the bullet (u)=690 m/s Penetration in trunk (d)=6.2 cm

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Q: A 7.80 g bullet is initially moving at 470 m/s just before it penetrates a tree trunk to a depth of…

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A: Solution:-Given thatmass of box(m)=32.5 kgdisplacement (s)=4.75 mConstant applied force (F)=145…

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Q: A 287-kg crate is being pushed across a horizontal floor by a force P that makes an angle of 17.1°…

A: Given  M = 287 kg  Coefficient of kinetic friction, u = 0.253  Force P makes angle 17.1 °   What is…

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Q: A 7.80-g bullet moving at 650 m/s penetrates a tree trunk to a depth of 6.50 cm. (a) Use work and…

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Q: 6) A 7.80-g bullet moving at 490 m/s penetrates a tree trunk to a depth of 4.6 cm. Use work and…

A: The mass of the bullet, m = 7.80 g = 7.80×10-3 kg The initial velocity of the bullet, vi = 490 m/s…

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Q: Ex 12 : Calculate the work done in blowing a soap bubble of radius 0.5 cm. Surface tension of soap…

A: Radius of soap bubble r = 0.5 cm = 0.005 m Surface tension of soap solution is T = 2.5 × 10- 3 N/m

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Q: A 7.80-g bullet moving at 660 m/s penetrates a tree trunk to a depth of 5.80 cm. (a) Use work and…

A:

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A: Visualize the Problem:

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A: It is given that,

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A: thank you

Q: A 12 kg block starts from rest and is pushed 20 meters up the sloping surface of a plane (37 degree…

A: Work done is given as W=F.s                                                 .......(1) from work…

Q: A 287-kg crate is being pushed across a horizontal floor by a force P that makes an angle of 17.1°…

A: The mass m=287 kg The angle θ=17.1° The coefficient of kinetic fraction μk=0.253