A 7.0 µF capacitor and a 9.0 µF capacitor are connected in series across a 6.0 kV potential difference. The charged capacitors are then disconnected from the source and connected to each other with terminals of like sign together. Find the charge on each capacitor (in mC) and the voltage across each capacitor (in V). (Due to the nature of this problem, do not use rounded intermediate values in your calculations—including answers submitted in WebAssign.)**7.0 µF capacitor**- Charge: _______ mC- Voltage: _______ V**9.0 µF capacitor**- Charge: _______ mC- Voltage: _______ VThere are no graphs or diagrams accompanying the text.

Given capacitance C1=7.0μF, C2=9.0μF Voltage V=6.0kV The circuit diagram: Since the two capacitors are in series therefore their equivalent capacitance will be Therefore the circuit will become Now we can see the voltage across the capacitor C is V. Therefore total charge on the capacitor is Q= C V. ..........(1)Now when the two capacitors C1 and C2 are connected in parallel the voltage across the two capacitors must be equal. For this the total charge Q will be distributed in such a way so that the potential across the two must be equal. So suppose the charge on capacitor C1 is q1 and charge on capacitor C2 is q2. Then But from conservation of charge this is the charge on capacitor C2. Therefore from equation (2) charge on capacitor C1 is this is the charge on capacitor C1. And voltage across each capacitor is

Answered: A 7.0 µF capacitor and a 9.0 pF…