A 67.5-kg skier encounters a dip in the snow's surface that has a circular cross section with a radius of curvature of 12.0 m, as shown below. The snow is so slippery it can be considered to be frictionless. If the skier's speed a point A is 9.64 m/s, what is the skier's speed at point B? (enter your answer to three significant figures) possibly useful: K+U, = K,+ U, + AQ K= (1/2)mv We mg Ugrav= mgh \r-12 m g=9.81 m/s? (FJnet = ma,= mv 9.64 m/s Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B What is the normal force exerted on the skier at point B? (enter your answer to three significant figures) Submit Request Answer

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A 67.5-kg skier encounters a dip in the snow's surface that has a circular cross section with a radius of curvature of 12.0 m, as shown below. The snow is so slippery it can be considered to be frictionless. If the skier's speed a point A is
9.64 m/s, what is the skier's speed at point B? (enter your answer to three significant figures)
possibly useful:
K, + U, = K, + U, + AQ
K = (1/2)mv2
W = mg
Ugrav = mgh
r 12 m
%3D
1.75 m
g = 9.81 m/s?
(FJnet = mac =
mv/r
9.64
m/s
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 4 attempts remaining
Part B
What is the normal force exerted on the skier at point B? (enter your answer to three significant figures)
Submit
Request Answer
Transcribed Image Text:A 67.5-kg skier encounters a dip in the snow's surface that has a circular cross section with a radius of curvature of 12.0 m, as shown below. The snow is so slippery it can be considered to be frictionless. If the skier's speed a point A is 9.64 m/s, what is the skier's speed at point B? (enter your answer to three significant figures) possibly useful: K, + U, = K, + U, + AQ K = (1/2)mv2 W = mg Ugrav = mgh r 12 m %3D 1.75 m g = 9.81 m/s? (FJnet = mac = mv/r 9.64 m/s Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B What is the normal force exerted on the skier at point B? (enter your answer to three significant figures) Submit Request Answer
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