A 64.0 kg cheetah accelerates from rest to its top speed of 30.7 m/s. HINT (a) How much net work (in J) is required for the cheetah to reach its top speed? (b) One food Calorie equals 4186 J. How many Calories of net work are required for the cheetah to reach its top speed? Note: Due to inefficiencies in converting chemical energy to mechanical energy, the amount calculated here is only a fraction of the energy that must be produced by the cheetah's body. Cal

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Chapter1: Units, Trigonometry. And Vectors
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### Educational Exercise: Kinetic Energy and Power Calculation for a Cheetah

**Problem Statement:**
A 64.0 kg cheetah accelerates from rest to its top speed of 30.7 m/s.

**(a) Calculation of Net Work:**
- **Question:** How much net work (in Joules) is required for the cheetah to reach its top speed?
- **Input Box:** [Insert the answer here in Joules (J)]

**(b) Conversion to Calories:**
- **Question:** One food Calorie equals 4186 Joules. How many Calories of net work are required for the cheetah to reach its top speed? 
  - **Note:** Due to inefficiencies in converting chemical energy to mechanical energy, the amount calculated here is only a fraction of the energy that must be produced by the cheetah's body.
- **Input Box:** [Insert the answer here in food Calories (Cal)]

### Hint:
To start solving this problem, remember the kinetic energy formula:
\[ KE = \frac{1}{2} m v^2 \]
where \( m \) is mass and \( v \) is velocity.

### No Graphs or Diagrams
There are no graphs or diagrams associated with this problem. The exercise focuses on textual information and calculation inputs for kinetic energy and energy conversion. 

This problem is designed to help students understand concepts of kinetic energy, work, and conversion between joules and calories.
Transcribed Image Text:### Educational Exercise: Kinetic Energy and Power Calculation for a Cheetah **Problem Statement:** A 64.0 kg cheetah accelerates from rest to its top speed of 30.7 m/s. **(a) Calculation of Net Work:** - **Question:** How much net work (in Joules) is required for the cheetah to reach its top speed? - **Input Box:** [Insert the answer here in Joules (J)] **(b) Conversion to Calories:** - **Question:** One food Calorie equals 4186 Joules. How many Calories of net work are required for the cheetah to reach its top speed? - **Note:** Due to inefficiencies in converting chemical energy to mechanical energy, the amount calculated here is only a fraction of the energy that must be produced by the cheetah's body. - **Input Box:** [Insert the answer here in food Calories (Cal)] ### Hint: To start solving this problem, remember the kinetic energy formula: \[ KE = \frac{1}{2} m v^2 \] where \( m \) is mass and \( v \) is velocity. ### No Graphs or Diagrams There are no graphs or diagrams associated with this problem. The exercise focuses on textual information and calculation inputs for kinetic energy and energy conversion. This problem is designed to help students understand concepts of kinetic energy, work, and conversion between joules and calories.
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