A 610 kg car pulling a 545 kg trailer accelerates forward at a rate of 2.25 m/s2. Assume frictional forces on the trailer are negligible. Ignore air drag. (a) Calculate the net force (in N) on the car. magnitude N ....... direction ---Select-- (b) Calculate the net force (in N) on the trailer. magnitude direction ---Select--- (c) What is the force (in N) exerted by the trailer on the car? magnitude direction ---Select---

Q: A 2.30-kg block starts from rest at the top of a 30.0° incline and slides a distance of 2.30 m down…

A: “Since you have posted a question with multiple sub parts, we will provide the solution only to the…

Q: When an ice hockey puck weighing 90 g is stationary on the ice, a minimal force of 0.2 N is…

A: Draw the free-body diagram of the puck.

Q: A 2200 kg car, initially travelling at 80.0 km/h West, slams on the brakes and it comes to rest over…

A:

Q: A 3.80-kg block starts from rest at the top of a 30.0° incline and slides a distance of 2.10 m down…

A:

Q: A 6.00kg block on a rough (µ=0.388) horizontal table is connected by a cord to a 2.50kg block…

A:

Q: Please answer fast While hauling a log in the back of a flatbed truck, a driver is pulled over by…

A:

Q: A 3.5 kg block is pushed along a horizontal floor by a force F of magnitude 20 N at an angle of 400…

A: Mass of block m = 3.5 kg F = 20 N θ = 40° Coefficient of kinetic friction  μk = 0.25 Block's…

Q: You are pulling a string with a force of 209N attatched to a heavy box of mass 27Kg across your…

A:

Q: An 8.0 kg object moving with an initial velocity of 8.0 m/s on a surface comes to rest due to…

A: m = 8 kg  Initial velocity (v) = 8.0 m/s  Horizontal distance (x) = 10 m  g =10 m/s2

Q: 1. An object of mass 10.1 kg is pushed directly from rest along a horizontal surface, a distance of…

A:

Q: A 27.0-kg box is released on a 27 ∘ incline and accelerates down the incline at 0.30 m/s^2 .…

A: component of gravitational force down the incline  = mgSin27° = 27×9.8×Sin27° = 120.12 N  friction…

Q: Example 5.13 Friction in horizontal motion You want to move a 500-N crate across a level floor. To…

A:

Q: A 50kg block is being pushed down a 16 degree slope by a force F of magnitude 250 N and directed at…

A:

Q: 2. Consider the system shown in the following figure. The coefficient of kinetic friction between…

A: Given that wA=283N Coefficient of kinetic friction=0.36 For part (a) velocity of block B is constant…

Q: g up a grade of 15 with an initial velocity of 30 m/s. The coefficient of static friction between…

A: GivenAngle, θ=15°Initial velocity, u=30 m/sCoefficient of static friction between the tires and the…

Q: A safe weighing 2000N is to be lowered at constant speed down the ramp 4m long from a truck 2m high;…

A: The net force acting on an object is equal to the product of mass and acceleration of the object. If…

Q: A box with a mass of 10.0 kg is placed on a hill that includes upwards at an angle of 30.0°. The…

A:

Q: 2.A dockworker applies a constant horizontal force of 80.0 N toa block of ice on a smooth horizontal…

A: Force ( F ) = 80 N  Displacement ( s ) = 11 m  Time ( t ) = 5 s  Initial velocity ( u ) = 0 m/s

Q: A constant force acts on a 5.0 kg object and reduces its velocity from 7.0 m/s to 3.0 m/s in a time…

A: v=3 m/s u=7 m/s t=3 s m=5 kg a=(v-u)/t a=(3-7)/3=-4/3 m/s^2

Q: 1. An object (8 kg) was given a kick at the bottom of an incline (20°) and it started with a…

A:

Q: A 262N crate resting on a plane inclined 23-degrees with the horizontal requires a 24.6N force to…

A: Given, The weight of the crate is W=262N The angle of inclination is θ=23o The initial velocity of…

Q: A group of young explorers invent a scheme to pull a ore car out of an sloping mine shaft at an…

A:

Newton's Second Law

Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows: