A 600 kg car pulling a 525 kg trailer accelerates forward at a rate of 2.09 m/s?. Assume frictional forces on the trailer are negligible. Ignore air drag. (a) Calculate the net force (in N) on the car. magnitude direction ---Select--- v (b) Calculate the net force (in N) on the trailer. magnitude N direction |---Select--- v (c) What is the force (in N) exerted by the trailer on the car? magnitude N direction Select-
A 600 kg car pulling a 525 kg trailer accelerates forward at a rate of 2.09 m/s?. Assume frictional forces on the trailer are negligible. Ignore air drag. (a) Calculate the net force (in N) on the car. magnitude direction ---Select--- v (b) Calculate the net force (in N) on the trailer. magnitude N direction |---Select--- v (c) What is the force (in N) exerted by the trailer on the car? magnitude N direction Select-
College Physics
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Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Physics Problem: Car and Trailer Dynamics
#### Problem Statement
A 600 kg car pulling a 525 kg trailer accelerates forward at a rate of 2.09 m/s². Assume frictional forces on the trailer are negligible. Ignore air drag.
**(a)** Calculate the net force (in N) on the car.
- **Magnitude**: [Input box for value] N
- **Direction**: [Dropdown for direction]
**(b)** Calculate the net force (in N) on the trailer.
- **Magnitude**: [Input box for value] N
- **Direction**: [Dropdown for direction]
**(c)** What is the force (in N) exerted by the trailer on the car?
- **Magnitude**: [Input box for value] N
- **Direction**: [Dropdown for direction]
**(d)** What is the resultant force exerted by the car on the road? (Assume that the forward direction is along the +x-direction to the right and that the +y-direction points upward. Enter the magnitude in N and the direction in degrees measured from the left of the −y-direction.)
- **Magnitude**: [Input box for value] N
- **Direction**: [Dropdown for direction] ° (measured from the left of the −y-direction)
#### Additional Information
- **Text Highlight**: The car has a mass of 600 kg.
- **Text Highlight**: The trailer has a mass of 525 kg.
- **Text Highlight**: Acceleration is 2.09 m/s².
### Solution Process
To solve these problems, you will need to apply Newton's Second Law of Motion, \( F = ma \), in calculating the forces. Here's a step-by-step guide:
1. **Find the net force on the car:**
- \( F_{\text{car}} = m_{\text{car}} \times a \)
2. **Find the net force on the trailer:**
- \( F_{\text{trailer}} = m_{\text{trailer}} \times a \)
3. **Calculate the force exerted by the trailer on the car by considering the interaction forces and the system of the car and trailer as one unit.**
4. **Determine the resultant force exerted by the car on the road by vector addition of forces, considering the direction of the](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbe5add6b-1715-412c-ae9e-e5ef4329e8a2%2F24712685-499f-4f6e-9494-9684c36d95b4%2Fqrlgdlt_processed.png&w=3840&q=75)
Transcribed Image Text:### Physics Problem: Car and Trailer Dynamics
#### Problem Statement
A 600 kg car pulling a 525 kg trailer accelerates forward at a rate of 2.09 m/s². Assume frictional forces on the trailer are negligible. Ignore air drag.
**(a)** Calculate the net force (in N) on the car.
- **Magnitude**: [Input box for value] N
- **Direction**: [Dropdown for direction]
**(b)** Calculate the net force (in N) on the trailer.
- **Magnitude**: [Input box for value] N
- **Direction**: [Dropdown for direction]
**(c)** What is the force (in N) exerted by the trailer on the car?
- **Magnitude**: [Input box for value] N
- **Direction**: [Dropdown for direction]
**(d)** What is the resultant force exerted by the car on the road? (Assume that the forward direction is along the +x-direction to the right and that the +y-direction points upward. Enter the magnitude in N and the direction in degrees measured from the left of the −y-direction.)
- **Magnitude**: [Input box for value] N
- **Direction**: [Dropdown for direction] ° (measured from the left of the −y-direction)
#### Additional Information
- **Text Highlight**: The car has a mass of 600 kg.
- **Text Highlight**: The trailer has a mass of 525 kg.
- **Text Highlight**: Acceleration is 2.09 m/s².
### Solution Process
To solve these problems, you will need to apply Newton's Second Law of Motion, \( F = ma \), in calculating the forces. Here's a step-by-step guide:
1. **Find the net force on the car:**
- \( F_{\text{car}} = m_{\text{car}} \times a \)
2. **Find the net force on the trailer:**
- \( F_{\text{trailer}} = m_{\text{trailer}} \times a \)
3. **Calculate the force exerted by the trailer on the car by considering the interaction forces and the system of the car and trailer as one unit.**
4. **Determine the resultant force exerted by the car on the road by vector addition of forces, considering the direction of the
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