A 60 g ball is tied to the end of a 30-cm-long string and swung in a vertical circle. The center of the circle, as shown in the figure, (Eigure 1) is 150 cm above the floor. The ball is swung at the minimum speed necessary to make it over the top without the string going slack Figure 150 cm 1001 > Part A If the string is released at the instant the ball is at the top of the loop, how far to the right does the ball hit the ground? Express your answer with the appropriate units. Az - 1.039 Submit m Provide Feedback Previous Answers Bequest Answer ? X Incorrect; Try Again; 3 attempts remaining Review your calculations and make sure you round to 2 significant figures in the last step. Next >

A 60 g ball is tied to the end of a 30-cm-long string and swung in a vertical circle. The center of the circle, as shown in the figure, (Eigure 1) is 150 cm above the floor. The ball is swung at the minimum speed necessary to make it over the top without the string going slack Figure 150 cm 1001 > Part A If the string is released at the instant the ball is at the top of the loop, how far to the right does the ball hit the ground? Express your answer with the appropriate units. Az - 1.039 Submit m Provide Feedback Previous Answers Bequest Answer ? X Incorrect; Try Again; 3 attempts remaining Review your calculations and make sure you round to 2 significant figures in the last step. Next >

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A ball of mass m = 0.275 kg swings in a vertical circular path on a string of length L = 0.850 m as shown. At the lowest point in its vertical path the ball is 1.5 m from the ground. If the string is cut when the ball is at the bottom of the string moving with a speed of 7.5 m/s, how far in the x-direction does the ball move before hitting the ground?
The 3.50 kg, 40.0-cm-diameter disk in (Figure 1) is spinning at 300 rpm. For help with math skills, you may want to review: Solving Algebraic Equations For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Nutcracker. Figure 3 1 of 1 Brake Part A How much friction force must the brake apply to the rim to bring the disk to a halt in 2.10 s ? Express your answer with the appropriate units. μÃ Value Submit Units Request Answer < Return to Assignment ? Provide Feedback
4. An object of mass m makes a loop-the-loop as shown. When it is upside down at point A, the normal force is found to be 2mg. a) What is the speed of the object at point A in terms of g and R? b) What is the normal force at point B, neglecting any friction of air resistance? Put your answer in terms of m and g. A B
A record is played by spinning the record so that a circular groove in the vinyl slides under the stylus. Suppose that a record turns at a rate of 33 1/3 rev. min, the groove being played is at a radius of 10.0 cm and the bumps in the grove are uniformly separated by 1.75 mm. At what rate (hits per second) do the bumps hit the stylus? Enter units as hertz (Hz). You will need v=rω ω is in rad/s and 1rev = 2 pi rad.
A student is swinging a ball of mass 0.323 kg in a vertical circle at constant speed, as shown in the figure below. (g indicates the direction of the acceleration due to gravity: directly downward.) The length of the string is 0.76 m. She measures the tension and finds that it is 5.601 times larger at the bottom of the circle than at the top. What is the speed of the swinging mass?
A mother pushes her child on a swing so that his speed is 9.7 m/s at the lowest point of his path. The swing is attached to a point 2.05 m above the child’s center of mass when the swing is motionless. What is the centripetal acceleration of the child at the low point in m/s2? What is the magnitude of the force that the child exerts on the seat at the lowest point if his mass is 19.5 kg in N?
A pail of water is being swung in a vertical circle at the end of a 0.55-m string. How slowly can the pail go through its top position without having the string go slack? O 3.9 m/s O 3.3 m/s O 5.4 m/s O 2.3 m/s O 3.1 m/s Save for Later Submit Answer
A 200 g block on a 58.0 cm -long string swings in a circle on a horizontal, frictionless table at 95.0 rpm You may want to review (Pages 186 - 189) Part A What is the speed of the block? Express your answer with the appropriate units. 5.46 Submit Part B μA 10.27 Submit m X Incorrect, Try Again; 5 attempts remaining S Previous Answers Request Answer What is the tension in the string? Express your answer with the appropriate units. μÅ 3 ? N ? Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining
A 200 kg mass hangs from a 300 m cable on Mars (g=3.71 m/s2). It is displaced left from equilibrium along an arc with length 30 m and released at t = 0. What is its position relative to equilibrium when t = 20 s? What is its acceleration?
A ball is on the end of a string. The ball is being swung in a vertical circle at a constant speed.The length of the string is 1.30 m. The mass of the ball is 2.10 kg. The maximum tension the string can withstand before breaking is 54.0 N.What is the maximum speed of the ball without the string breaking when the ball is at the top of the circle (Point A in the figure)?
Experimental Ezra ties a 59.4 g tennis ball to a string and swings it in a vertical circle. Ezra swings the ball so that it always has constant speed of v = 4.82 m/s. The radius of the swing is r = 0.787 m and Ezra's hand is H = 1.40 m above the ground as shown. y H
A pendulum is 0.890 m long, and the bob has a mass of 1.00 kg. At the bottom of its swing, the bob’s speed is 1.60 m/s. a. What is the tension in the string at the bottom of the swing? answer in N b. The tension is greater than the weight of the bob because of which of the following? its horizontal component is increasing from zero. the bob has zero acceleration. the bob has a downward acceleration, so the net Fy must be downward. the bob has an upward acceleration, so the net Fy must be upward.