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A 6.95 kg ball moving initially at 10.0 m/s hits a 5.17 kg ball at rest, in a linear elastic collision. What is the speed of the first ball after the collision? (the one initially moving) 1.21 m/s What is the speed of the second ball after the collision? (the one initially at rest) Number Units

A 6.95 kg ball moving initially at 10.0 m/s hits a 5.17 kg ball at rest, in a linear elastic collision. What is the speed of the first ball after the collision? (the one initially moving) 1.21 m/s What is the speed of the second ball after the collision? (the one initially at rest) Number Units

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A6.95 kg ball moving initially at 10.0 m/s hits a 5.17 kg ball at rest, in a linear elastic collision. What is the speed of the first ball after the collision? (the one initially moving) 1.21 m/s What is the speed of the second ball after the collision? (the one initially at rest) Number Units
Transcribed Image Text:A6.95 kg ball moving initially at 10.0 m/s hits a 5.17 kg ball at rest, in a linear elastic collision. What is the speed of the first ball after the collision? (the one initially moving) 1.21 m/s What is the speed of the second ball after the collision? (the one initially at rest) Number Units
Expert Solution
Step 1

Consider the speed of first and second body after the collision is v1& v2 respectively.

Apply the conservation of moment.

Initial momentum=final momentum

6.95×10+5.17×0=6=95v1+5.17v2

69.5= 6.95v1+5.17v2  ......... (1)

Apply the conservation of energy

Initial kinetic energy = final kinetic energy

1/2×6.95×10^2=1/2×6.95×v1^2+1/2×5.17×v2^2

695=6.95v1^2+5.17v2^2   ....... (2)

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