College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem 7**
A \(6.5 \times 10^{12}\) kg object is \(3.2 \times 10^{4}\) m away from a 3,800 kg object. Calculate the force of gravity between them.
The force of gravity (\(F_g\)) calculated seems to be \(16.6073\) N (as noted in handwriting).
This exercises involves applying the formula for gravitational force:
\[
F_g = \frac{G \cdot m_1 \cdot m_2}{r^2}
\]
Where:
- \(G\) is the gravitational constant \((6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2)\)
- \(m_1\) and \(m_2\) are the masses of the objects
- \(r\) is the distance between the centers of the two objects](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1b03dd43-cefb-41e0-a65e-fca4b6d6cf28%2F0bf9f729-6a3b-4e05-9ff0-c5ecf2f276f6%2Fyt8sx6n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 7**
A \(6.5 \times 10^{12}\) kg object is \(3.2 \times 10^{4}\) m away from a 3,800 kg object. Calculate the force of gravity between them.
The force of gravity (\(F_g\)) calculated seems to be \(16.6073\) N (as noted in handwriting).
This exercises involves applying the formula for gravitational force:
\[
F_g = \frac{G \cdot m_1 \cdot m_2}{r^2}
\]
Where:
- \(G\) is the gravitational constant \((6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2)\)
- \(m_1\) and \(m_2\) are the masses of the objects
- \(r\) is the distance between the centers of the two objects
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