Homework Help is Here – Start Your Trial Now!
Science
Physics
A 6.5×10¹2 kg object is 3.2×10 m away from a 3,800 kg object. Calculate the force of gravity between them. FD = 110,673

A 6.5×10¹2 kg object is 3.2×10 m away from a 3,800 kg object. Calculate the force of gravity between them. FD = 110,673

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
See similar textbooks
icon
Related questions
Topic Video
Question
**Problem 7** A \(6.5 \times 10^{12}\) kg object is \(3.2 \times 10^{4}\) m away from a 3,800 kg object. Calculate the force of gravity between them. The force of gravity (\(F_g\)) calculated seems to be \(16.6073\) N (as noted in handwriting). This exercises involves applying the formula for gravitational force: \[ F_g = \frac{G \cdot m_1 \cdot m_2}{r^2} \] Where: - \(G\) is the gravitational constant \((6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2)\) - \(m_1\) and \(m_2\) are the masses of the objects - \(r\) is the distance between the centers of the two objects
Transcribed Image Text:**Problem 7** A \(6.5 \times 10^{12}\) kg object is \(3.2 \times 10^{4}\) m away from a 3,800 kg object. Calculate the force of gravity between them. The force of gravity (\(F_g\)) calculated seems to be \(16.6073\) N (as noted in handwriting). This exercises involves applying the formula for gravitational force: \[ F_g = \frac{G \cdot m_1 \cdot m_2}{r^2} \] Where: - \(G\) is the gravitational constant \((6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2)\) - \(m_1\) and \(m_2\) are the masses of the objects - \(r\) is the distance between the centers of the two objects
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
First law of motion
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON
SEE MORE TEXTBOOKS