A 5KVA, 240/120 V single phase transformer has the following parameters: R1 = 0.06 Q R2 = 0.015 Q X1 = 0.18 Q X2 = 0.045 Q Rc =2000 0 Xm = 400 Q Transformer secondary winding feeds an inductive load of 5KVA power factor 0.9 at 120V rated voltage. Way using the T equivalent circuit, calculate the primary voltage of the transformer, primary current and find the power factor. What is the efficiency of the transformer? X2 R2 m R, V1 = V l1 = A V, Rc1 V2 V2 cose = n = % a u ww m

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A 5KVA, 240/120 V single phase transformer has the following parameters:
R1 = 0.06 Q
R2 = 0.015 0
X1 = 0.18 Q
X2 = 0.045 Q
Rc =2000 Q
Xm = 400 0
Transformer secondary winding feeds an inductive load of 5KVA power
factor 0.9 at 120V rated voltage. Way using the T equivalent circuit,
calculate the primary voltage of the transformer, primary current and find
the power factor. What is the efficiency of the transformer?
R1
X1
R2
m
V1=
V
l1 =
A
V,
V2
V2
cose =
Xm1
n =
%
a
Transcribed Image Text:A 5KVA, 240/120 V single phase transformer has the following parameters: R1 = 0.06 Q R2 = 0.015 0 X1 = 0.18 Q X2 = 0.045 Q Rc =2000 Q Xm = 400 0 Transformer secondary winding feeds an inductive load of 5KVA power factor 0.9 at 120V rated voltage. Way using the T equivalent circuit, calculate the primary voltage of the transformer, primary current and find the power factor. What is the efficiency of the transformer? R1 X1 R2 m V1= V l1 = A V, V2 V2 cose = Xm1 n = % a
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