Q: Tests on a spring showed that 1000-N of force was required to compress the spring 0.5-m. The spring…

A: Given data: The force applied is F=1000 N. The compression in spring is x=0.5 m. The mass of ball…

Q: A toy spring launcher is used to launch a 10.5 g object into the air. The spring of the launcher is…

A:

Q: An elevator car of mass 800 kg falls from rest 3.00 m, hits a buffer spring, and then travels an…

A:

Q: 1 of 1 Previous Answers Request Answer Submit Incorrect; Try Again; 9 attempts remaining Part D…

A: Using the conservation of energy,            The spring potential energy = potential energy gained…

Q: As shown in the figure below, a box of mass m = 7.00 kg is sliding across a horizontal frictionless…

A: By the conservation of energy, the total kinetic energy (K.E) gained by the block will be converted…

Q: A block of mass m = 3.70 kg is dropped from height h = 43.0 cm onto a spring of spring constant k =…

A: Given, Mass of the block, m = 3.70 kg height above the spring, h = 43.0 cm = 0.43 m spring constant,…

Q: 21A spring with spring constant 150 N/m is on a 53 frictionless inclined plane as shown in the…

A: Given: Spring constant, K=150 N/m Block's mass, m=3 kg Angle made by inclined plane with horizontal,…

Q: A 15-kg collar travels down a smooth slope as shown. Determine S1 speed If the S2 speed is 28 m/s.…

A: Given that,Mass of collar (m) = 15 kgSpeed v2 = 28 m/secOriginal length (x) = 9 mValue of k = 42…

Q: The mass m is attached to a spring of free length b and stiffness k. The coefficient of friction…

A: Given: The mass and spring are attached to each other of free length. The acceleration of mass is…

Q: 25-kg child uses a pogo stick to bounce up and down. The spring constant, k, of the toy equals 8750…

A:

Q: A 500-g block is released from rest and slides down a frictionless track that begins 2.50 m above…

A: SOlution: Given that m  500 g = 0.5 kg h = 2.5 m k = 10 N/m

Q: A spring has a constant 9f 200N/m. It is compressed 3cm and a small stone of 0.500kg is resting…

A:

Q: Determine the percent increase in the potential energy of the spring if it is stretched from 4.00 cm…

A: The expression for potential energy is U=12kx2 Here,k  is the spring constant,  x is the compressed…

Q: A 7.2-kg mass is hanging from the ceiling of an elevator by a spring with spring constant k = 150N/m…

A:

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.